Thread: Why is this free corruption the heap?

Hi there,

Doing something very simple here, not sure why I'm getting heap corruption at run time.
This function was much longer but I stripped it down to figure out what's wrong::

Code:

bool DeleteRecord(void){

	StudentRecord** delTemp; // temporary copy of DB used to resize array when adding

	delTemp = (StudentRecord**)malloc(g_numRecords * sizeof(StudentRecord*));
   for(count=0;count<g_numRecords-1;count++){
		delTemp[count]=(StudentRecord *)malloc(sizeof(StudentRecord));
		delTemp[count]->firstname=(char *)malloc(sizeof(char));//malloc fname 
		delTemp[count]->lastname=(char *)malloc(sizeof(char));//malloc lname
   }
	printf("malloced\n");
	delTemp[0]->firstname="........yous";
	printf("delTemp[0]->firstname=%s\n", delTemp[0]->firstname);
	delTemp[0]->lastname="youtwo";
	printf("delTemp[0]->lastnamename=%s\n", delTemp[0]->lastname);
	delTemp[0]->id=22;
	delTemp[0]->mark=33;
	printf("deltemp 0 id, mark: %d, %f\n", delTemp[0]->id,delTemp[0]->mark); 

	free(delTemp[0]->firstname);
	printf("freed fname\n");
	free(delTemp[0]->lastname);
	printf("freed lname\n");
	free(delTemp);
	printf("freed deltemp\n");



	return true;
}

Code:

struct StudentRecord
{
	char* firstname;
	char* lastname;
	int id;
	float mark;
};

I get heap corruption trying to free the memory I just malloced?
Any suggestions?
Thanks!!!