Why is this free corruption the heap?

Hi there,

Doing something very simple here, not sure why I'm getting heap corruption at run time.
This function was much longer but I stripped it down to figure out what's wrong::

Code:

---

bool DeleteRecord(void){

        StudentRecord** delTemp; // temporary copy of DB used to resize array when adding

        delTemp = (StudentRecord**)malloc(g_numRecords * sizeof(StudentRecord*));
  for(count=0;count<g_numRecords-1;count++){
                delTemp[count]=(StudentRecord *)malloc(sizeof(StudentRecord));
                delTemp[count]->firstname=(char *)malloc(sizeof(char));//malloc fname
                delTemp[count]->lastname=(char *)malloc(sizeof(char));//malloc lname
  }
        printf("malloced\n");
        delTemp[0]->firstname="........yous";
        printf("delTemp[0]->firstname=%s\n", delTemp[0]->firstname);
        delTemp[0]->lastname="youtwo";
        printf("delTemp[0]->lastnamename=%s\n", delTemp[0]->lastname);
        delTemp[0]->id=22;
        delTemp[0]->mark=33;
        printf("deltemp 0 id, mark: %d, %f\n", delTemp[0]->id,delTemp[0]->mark);

        free(delTemp[0]->firstname);
        printf("freed fname\n");
        free(delTemp[0]->lastname);
        printf("freed lname\n");
        free(delTemp);
        printf("freed deltemp\n");



        return true;
}

---

Code:

---

struct StudentRecord
{
        char* firstname;
        char* lastname;
        int id;
        float mark;
};

---

I get heap corruption trying to free the memory I just malloced?
Any suggestions?
Thanks!!!

You don't need to have a "-1" in there. Why are you using a pointer to a pointer?

Code:

---

struct foo *bar;
bar = malloc( N * sizeof *bar );
for( x = 0; x < N; x++ )
{
    bar[ x ].a = b;
    bar[ x ].y = z;
}
...

free( bar );

---

I'm not sure why you're using a pointer to a pointer here.

Quote:

---

delTemp[count]->firstname=(char *)malloc(sizeof(char));//malloc fname
delTemp[count]->lastname=(char *)malloc(sizeof(char));//malloc lname

---

Why are you allocating 1 char for each of their first and last names? Did you mean to actually have more than one character?


Quzah.