I have this say:
Later on i have this : struct temp1 ARRAY[] = { some stuff};Code:struct temp1 { char *p; short len; };
So instead of the above i want to do this:
introduce another struct and want to do this:
ThanksCode:struct temp2 { struct temp1 ARRAY[]; }; struct temp2 *ptr; How do i assing ARRAY to some values is it like this: ptr->ARRAY[]={ some stuff}???
Here is an example to do it:
Code:#include<stdio.h> #include<stdlib.h> struct temp1 { char *p; short len; }; struct temp2 { struct temp1 arr[3]; }*ptr; int main(void) { ptr=malloc(50); (ptr->arr[0]).p="HELLO"; (ptr->arr[0]).len=56; printf("%s\n%d",(ptr->arr[0]).p,(ptr->arr[0]).len); return 0; }
HOPE YOU UNDERSTAND.......
By associating with wise people you will become wise yourself
It's fine to celebrate success but it is more important to heed the lessons of failure
We've got to put a lot of money into changing behavior
PC specifications- 512MB RAM, Windows XP sp3, 2.79 GHz pentium D.
IDE- Microsoft Visual Studio 2008 Express Edition
Thats great but my problem is i want to assign something to the array at global scope.??
Sorry should of said that!
I dont think if you can do that coz you need to have space allocated for ptr using malloc first which I dont think can be done globally. Without malloc ptr will be uninitialized pointer which will point in any arbritrary address causing segmentation fault.
Someone else can throw some light on it.
HOPE YOU UNDERSTAND.......
By associating with wise people you will become wise yourself
It's fine to celebrate success but it is more important to heed the lessons of failure
We've got to put a lot of money into changing behavior
PC specifications- 512MB RAM, Windows XP sp3, 2.79 GHz pentium D.
IDE- Microsoft Visual Studio 2008 Express Edition
Also, arrays have a fixed size so you can't declare an array like this:
You can however initialize it with something in which case the size is set implicitly:Code:int arr[];
Code:int arr[] = {1, 2, 3};
