Thread: A Linked Stack in C

Hello. I have a question with my linked stack implementation in C. I'm pretty new to C and especially pointers. Any help will be greatly appreciated.

First of all, I tested my linked stack implementation with the following code:

Code:

//Just so you know
typedef struct LinkedStack linkedstack;
typedef struct StackNode node;

struct StackNode{
	char info;
	struct StackNode *link;
};

struct LinkedStack{
	struct StackNode *top;
};

main(){
	linkedstack s;
	char c;
	char vowels[] = "aeiou";
	int i = 0;
	
	CreateStack(&s);
	
	while(i < strlen(vowels)){
		push(&s, vowels[i]);
		i++;
	}
	
	while(!isEmpty(&s)){
		char foo = pop(&s);
		printf("%s%s", &foo, "\n");
	}
	
	char bar = pop(&s);
}

From the above code, I expected the following output:

Code:

u
o
i
e
a
StackUnderflow occurred!

However, the output I get looks like this: after the vowels, there will be an unwanted ascii character. When I run it from the command line, I get the clubs character. Ran from Notepad++'s NppExec plugin, I get a bar ("|").

I figure that my mistake is in my implementation of push and pop (but I am heavily inclined to think that my push is perfect, that my pop is the defective one), as it messily deals with pointers. Here's my code:

Code:

void push(linkedstack *stack, char me){
	node *NewNode;
	NewNode = (node *) malloc(sizeof(node));
	
	if(NewNode == NULL){
		StackOverflow();
	}
	else{
		NewNode->info = me;
		NewNode->link = stack->top;
		stack->top = NewNode;
	}
}

char pop(linkedstack *stack){
	char temp;
	node *node;
	
	if(isEmpty(stack)){
		StackUnderflow();
	}
	else{
		node = stack->top;
		temp = (*node).info;
		stack->top = (*node).link;
		free(node);
	}
	
	return temp;
}

Now, I've seen implementations of pop that takes in a stack pointer and a pointer to a "placeholder" i.e., to where the popped value will be stored. However, due to matters of style rooted in my OO (Java) training, I am trying to avoid that. The pop implemenations I've seen return void (as the popped element is stored in the passed pointer). I want to return a char, point blank.

Is this possible in C or am I making myself suffer by thinking encumbered by OO? Any pointers (no pun intended) to the proper direction will be appreciated. Much thanks.

I think that the problem lies here:

Code:

printf("%s%s", &foo, "\n");

it should be:

Code:

printf("%c\n", foo);

since you want to print a char, not a string.

Hello laserlight. I tried what you suggested and received the following output:

Code:

K
K
K
K
K
StackUnderflow occurred!

No unwanted ascii character this time although the output is more unexpected. I tried to add a printf just before the return statement in pop. I got the following output

Code:

From the pop function:uK
From the pop function:oK
From the pop function:iK
From the pop function:eK
From the pop function:aK
StackUnderflow occurred!

I am afraid that although I would write the program a little differently, I do not see anything in what you have shown that would result in such an output. I suggest that you post the smallest and simplest compilable program that demonstrates the problem.

Why do you keep calling pop again after you know isEmpty returns empty?


Quzah.

Originally Posted by skytreader

laserlight, Adak, much as I'd like to post my code here, I really can't. This is schoolwork and one of my classmates might go googling, stumble upon here and we'd have the same code. And, lest I be accussed of fraud or anything along those lines, implementing a stack is only a trivial part of the problem.

I asked you to post the smallest and simplest compilable program that demonstrates the problem, not your current code in its entirety. It may well be the case that you will discover the root of the problem while coming up with such a program and thus be able to fix your current program on your own. Even if you don't the fact that you have posted here provides some measure of protection against accusations of plagiarism.

So you had good working code for this stack, all along, and you're just messing around, yanking our chains.

I'd love to tell you how damn inconsiderate you are, but I know I couldn't really communicate that to someone as self-centered as yourself, in a public forum.

Originally Posted by laserlight

Even if you don't the fact that you have posted here provides some measure of protection against accusations of plagiarism.

In a moment's thought, I didn't realize that.

My apologies if my being stubborn caused inconveniences. Again, I did not use the working code given in our reference book because I wanted my own shot at going at C. My approach and the book's approach are different (especially in terms of pop).

I was about to post my problematic code now when I realized what made my approach wrong.

From my first post:

Code:

main(){
	linkedstack s;
	char c;
	char vowels[] = "aeiou";
	int i = 0;
	
	CreateStack(&s);
	
	while(i < strlen(vowels)){
		push(&s, vowels[i]);
		i++;
	}
	
	while(!isEmpty(&s)){
		char foo = pop(&s);
		printf("%s%s", &foo, "\n"); //<--This made it wrong!
	}
	
	char bar = pop(&s);
}

I passed the address of foo to printf, hence the messy output. On my third post, it seems that I have already fixed the problem (see the same line) without having to remove 'foo' only I didn't realize it. So I removed foo and directly passed pop(&s) and thought that to be the solution.

Code:

//In the first code listing of my third post, I am no longer passing the address of foo.
printf("%s%c%c", "popped ", foo, '\n');

Well...that's pretty much it. Thanks to everyone who lent me hand. It was never my intention to waste your time with the trivial part of my problem. I am sorry if I made you feel like that.

EDIT: laserlight, I'm sorry. You pointed that out to me in your first reply. I didn't see that 'foo' part. What took my attention is the "%c\n" argument and that's the only thing I changed. My apologies.