integers... help

This is a discussion on integers... help within the C Programming forums, part of the General Programming Boards category; hi, i'm trying to do run this program... but there's something wrong... when i tried entering 34567 the result would ...

  1. #1
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    Post integers... help

    hi, i'm trying to do run this program...
    but there's something wrong...
    when i tried entering 34567
    the result would be negative integers, don't know why
    please i need your help

    insert
    Code:
     
    #include<stdio.h>
    int main()
    {
    int input;
    int first;
    int second;
    int third;
    int fourth;
    int fifth;
    
    printf("Enter your digit: ");
    scanf("%d", & input);
    printf("\n");
    
    first = input % 10;
    second = (input % 100)/10;
    third = (input % 1000)/100;
    fourth = (input % 10000)/1000;
    fifth = (input % 100000)/10000;
    
    printf("first: %d", first);
    printf("second: %d", second);
    printf("third: %d", third);
    printf("fourth: %d", fourth);
    printf("fifth: %d", fifth);
    
    return 0;
    
    }

  2. #2
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    I dont see the output as negative integer....

  3. #3
    Epy
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    Are you compiling this under DOS or somewhere else where integers would be 16-bits and bound between -32768 and 32767? There's nothing wrong with your code that I can see...you could try it with longs instead of ints.

  4. #4
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    May I suggest you indent your source code? It helps dramatically with source code readability . . .

    Code:
    #include <stdio.h>
    
    int main() {
        int input;
        int first, second, third, fourth, fifth;
    
        printf("Enter your digit: ");
        scanf("%d", & input);
        printf("\n");
    
        first = input % 10;
        second = (input % 100)/10;
        third = (input % 1000)/100;
        fourth = (input % 10000)/1000;
        fifth = (input % 100000)/10000;
    
        printf("first: %d", first);
        printf("second: %d", second);
        printf("third: %d", third);
        printf("fourth: %d", fourth);
        printf("fifth: %d", fifth);
    
        return 0;
    }
    And yes, as previously mentioned, old compilers (such as Turbo C) and old platforms (such as the 8086) had a maximum range for ints of -32,768 to 32,767 (32-bit platforms and compilers usually have a range of -2,147,483,647 to 2,147,483,648, some 64-bit platforms may define the long type to be from -9,223,372,036,854,775,808 to 9,223,372,036,854,775,807).

    If you are using a compiler old enough to have the int type as 16 bits, then I strongly suggest you find another compiler.
    -- strange

    There is no Darkness in Eternity
    Only Light too dim for us to see

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