Thread: i need help with this function, I can't get sizeof(char) to work properly

this code works like this

lets say we have a string word' = "abcdabc";

and we want to erase a word that is included in word'

if word = "abc" we want to make word' = " d ";

i ve done this so far

Code:

#include <stdio.h>
#include <string.h>

void str_return(char input[],char strsearch[]){
     
     int i,z;
   //  printf("%s\n",input);
   //  printf("%s\n",strsearch);
    //getchar();

         for (i=0;i<14;i++){
    
          if (&input[i] == strstr(input,strsearch) && strstr(input,strsearch)!=NULL){
                    
                    for (z=i;z<i+strlen(strsearch);z++){
                    input[z] = ' ';
                    }
                    
                    }

            }

     }
int main(void){
    
    char x[] = "lolsopaasdlol";
    int i=0,y=0,z;
    printf("%d\n",sizeof(x)/sizeof(char));
    str_return(x,"asd");
    
    printf("%s\n",x);
     
         // system("pause");
    
    return 0;
    
}

here -> for (i=0;i<14;i++){

i want to put where 14 sizeof(input)/sizeof(char)

but the sizeof(input)/sizeof(char) inside the function is 4 while in main() function it's 14

why is that?

Thanks

Originally Posted by jackhasf

why is that?

Because x is a char array, and "input" is a char* (you should use char *input in the param list, it means the same thing and may be less confusing for you).

Use strlen+1 instead.