Say we have 2 arrays of size ten, the second array as 6 ints in it.
If i do a memcpy(array1, array2 10);
Will i get rubbish in the after the 6 spot in the array1 or will memcpy set them to null;
ie what be the valueof array1[7] - [9]
Is memset more safer before the memcpy on the array?
Thanks
Last edited by newbie30; 12-09-2009 at 06:29 AM.
memcpy will only copy memory from one place to another. It will not in any way manipulate anything by setting it to 0 or null. So the answer to that question is: if there is rubbish in the array you copy, then yes, the destination will have it too.
The second questions depends on what you use it for. For example, do you somehow depend on some elements that are not in use being 0? If so, then yes. Otherwise, it's probably a no.
Originally Posted by Adak
That wont work, the size parameter is number of bytes. If your array consists of ints, 10 bytes wont cover the whole array.
