Thread: Basic question - How to wait before asking another input?

Hi everyone,

Within a function A, I have a printf that asks for a login and another one that asks for a password.

When I call that function from the main function, it works... it waits for me to insert the first and then the second.

The problem occurs when I call the function A from another function B, it goes directly to the second printf without letting me to insert the first one.

Here is part of the code:

Code:

printf("Login:\n");
fgets(login,sizeof(login),stdin);

printf("Password:\n");
fgets(password,sizeof(password), stdin);

Any ideas?

Thanks in advance.

There's probably a newline leftover in the input stream, but to be sure post the code in the calling function.

Hi itCbitC,

It gives me the same problem!

I've made some more tests.

If if call it this way (within the main function):

Code:

goToLogin();

it goes without problems.

But with something like this (within the main function):

Code:

.
.
.
case 'L':
if(goToLogin())
  printf("sucess\n");
.
.
.

It happens the same problem.. It shows both printfs at the same time and I can only enter one input.

To be honest, No.

I'm new to this stuff.

Can you explain?

int function, returns 1 in case of sucess

When you get a char from the user, the newline char '\n' is left behind on the input stream.

In your first example, you don't get a char from the user first, so there is no newline in the buffer. In the second example, you do - so you have one.

Pull the newline out of the buffer, after the char input, and see if that doesn't fix your problem:

junkVariable = getchar();

(reading your post right now)

OK i got it! I'm just starting on this so sorry for my incompetence.

getchar(); between the first printf and fgets solved the problem

Thanks everyone for the great help