"int (x*)[5];" Could anyone tells me what's the type of x?

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    "int (x*)[5];" Could anyone tells me what's the type of x?

    "int (x*)[5];"
    Is x a pointer to "int ...[]"?

  2. #2
    C++ Witch laserlight's Avatar
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    Quote Originally Posted by hchingwong
    Is x a pointer to "int ...[]"?
    Yes, x is a pointer to an int[5].
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    Thank you laserlight.

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    C++ Witch laserlight's Avatar
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    Oh wait, I'm sorry. I misread. Actually, that should result in a compile error. I was thinking of:
    Code:
    int (*x)[5];
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    DESTINY BEN10's Avatar
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    Quote Originally Posted by laserlight View Post
    Oh wait, I'm sorry. I misread.
    Reading your first post, I was shocked why didn't I see this type of pointer syntax before. and was about to search the internet for it.
    HOPE YOU UNDERSTAND.......

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    Cool

    X seems like a pointer point to an integer array that contain 5 members.
    Because complier give me an warning: "assignment from incompatible pointer type" in this case.
    Code:
    int (*x)[5];
    int b[3];
    x = &b;
    And this one pass without warning.
    Code:
    int b[5];
    This's the first time I ask a question on the forum. So,
    thank you everybody.

  7. #7
    DESTINY BEN10's Avatar
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    Quote Originally Posted by hchingwong View Post
    X seems like a pointer point to an integer array that contain 5 members.
    Because complier give me an warning: "assignment from incompatible pointer type" in this case.
    Code:
    int (*x)[5];
    int b[3];
    x = &b;
    And this one pass without warning.
    Code:
    int b[5];
    This's the first time I ask a question on the forum. So,
    thank you everybody.
    Code:
    int (*x)[5];
    Here x is a pointer pointing to an array having 5 ints. So, when you do this
    Code:
    int b[3];
    x=&b;
    You're assigning x to an array having 3 ints which is contrary to your declaration of x. That's why you get warning.
    HOPE YOU UNDERSTAND.......

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    Quote Originally Posted by hchingwong View Post
    X seems like a pointer point to an integer array that contain 5 members.
    Because complier give me an warning: "assignment from incompatible pointer type" in this case.
    Code:
    int (*x)[5];
    int b[3];
    x = &b;
    If you really wanted to, you could finagle something like
    Code:
    int (*x)[5];
    int b[3];
    x = (int (*)[5]) &b;

  9. #9
    Registered User slingerland3g's Avatar
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    Identifier Type-- int

    Name/Pointer--------- (x*) /*Can be a name or pointer to said type( this is needed to help set up the compiler to set up memory constraints */

    Space/Memory used -------------[5] /* how much memory should the compiler set aside. If not initialized, then this must be assigned later or malloc must be used for the pointed to memory address */



    Try this on for size:


    Code:
    typedef int (*pfunc)(void);
    pfunc Foo;

    Typedef
    Last edited by slingerland3g; 12-07-2009 at 01:26 PM.

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