Thread: Character reading problem

Hi,

Please take a look at this. It's only basic, since I'm doing my foundations course in C at university.

When I run the compiled programme, I get the following output:

Code:

[ec09411@dil027 8_3]$ ./Lab8_3
Enter an integer (): 4
Even
Continue (y/n): Enter an integer (): ^C
[ec09411@dil027 8_3]$

So I never get to input whether or not I want to continue (y/n). It just skips straight onto the while and loops round. Any ideas? Maybe it's just a tiny error, but I'll be damned if I can see it. Thanks!

Code:

#include <stdio.h>

int even(int input);

int main(void) {
    char contin;
    int input;

    do {
        contin = 0;

        printf("Enter an integer: ");
        scanf("%d", &input);

        if (even(input)) {
            printf("Even\n");
        } else {
            printf("Odd\n");
        }

        printf("Continue (y/n): ");
        scanf("%c", &contin);
    } while (contin != 'n');

    return 0;
}

int even(int input) {
    return !(input%2);
}
/*End of programme*/

I was about to say that you need to fflush(stdin) before your 2nd scanf (it's reading your carriage return as the next char I think), but I forgot that's undefined. Check out this thread: alternative for fflush(stdin) on some better things to use than just plain scanf.

Awesome guys. Thank you. That's one to be passed around.