Doubt with scaning characters

This is a discussion on Doubt with scaning characters within the C Programming forums, part of the General Programming Boards category; Hi all, for a CS project I need to make a menu, so the user must input values from 1 ...

  1. #1
    Registered User georgio777's Avatar
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    Doubt with scaning characters

    Hi all, for a CS project I need to make a menu, so the user must input values from 1 to 12 and q to exit the program.

    My main problem is that I am using getchar() to scan the menu selection.

    So inputs from 1 to 9 and q works, but 10 to 12 doesn't since getchar only supports ONE character.

    My first changes were to establish the switch cases to integers between range of 10 to 12.

    But still I need a suggestion of how to make the input 10, 11 and 12 to work.

    Here is the code:

    Code:
    #include <stdio.h>
    #include <stdlib.h>
    #include "prints.h"
    #include "exams.h"
    #include "guessyn.h"
    #include "guessmn.h"
    #include "diceg.h"
    #include "largestn.h"
    #include "distance.h"
    #include "areapara.h"
    #include "areatrape.h"
    #include "perimepoly.h"
    #include "arrayv.h"
    #include "arrayc.h"
    
    int main ()
    {
    	int selection;
    	do{
    	printf("Choose a skill to practice:\n");
    	printf("1) Print shapes\n");
    	printf("2) Exam score\n");
    	printf("3) I guess your number\n");
    	printf("4) Guess my number\n");
    	printf("5) Dice game\n");
    	printf("6) Largest number\n");
    	printf("7) Distance\n");
    	printf("8) Area of parallelogram\n");
    	printf("9) Area of trapezoid\n");
    	printf("10) Perimeter of polygon\n");
    	printf("11) Array vowel\n");
    	printf("12) Array consonant\n");
    	printf("q) Quit\n");
    	printf("\n");
    	printf("Enter selection: ");
    	selection = getchar();
    	while ( getchar() != '\n');
    	while ( selection != '1' && selection != '2' && selection != '3' && selection != '4' && selection != '5' && selection != '6'
    	&& selection != '7' && selection != '8' && selection != '9' && selection != 10 && selection != 11 && selection != 12
    	&& selection != 'q' )
    	{
    		printf("\n");
    		printf("Wrong input!!! Please try again...\n");
    		printf("\n");
    		printf("Enter selection: ");
    		selection = getchar();
    		while ( getchar() != '\n');
    	}
    	printf("\n");
    	switch( selection ){
    	case '1': prints(); break;
    	case '2': exams(); break;
    	case '3': guessyn(); break;
    	case '4': guessmn(); break;
    	case '5': diceg(); break;
    	case '6': largestn(); break;
    	case '7': distance(); break;
    	case '8': areapara(); break;
    	case '9': areatrape(); break;
    	case 10: perimepoly(); break;
    	case 11: arrayv(); break;
    	case 12: arrayc(); break;
    	case 'q': 
    		printf("Thanks for playing!");
    		return EXIT_SUCCESS;
    	}
    	printf("\n");
    	}while( selection == selection );
    }
    Changes I made are in red

  2. #2
    C++ Witch laserlight's Avatar
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    Instead of using getchar(), use say, scanf() to read into an int.
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  3. #3
    Registered User georgio777's Avatar
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    Quote Originally Posted by laserlight View Post
    Instead of using getchar(), use say, scanf() to read into an int.
    That's a good suggestion, but I need to still maintain characters for the 'q' value.

    What I'm trying to do is find a way that both characters and integers can be stored in a integer.
    Last edited by georgio777; 11-16-2009 at 10:38 PM.

  4. #4
    C++ Witch laserlight's Avatar
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    Ah yes, I did not notice that. In that case, you have do a little parsing, methinks. Read the input as a string, then determine if it is a number or a letter. If it is a letter, that is easy, you just use it. If it is a number, you then convert it to the number value, e.g., by using strtol() (which can actually be used to determine if the input is a number).
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  5. #5
    Registered User georgio777's Avatar
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    Quote Originally Posted by laserlight View Post
    Ah yes, I did not notice that. In that case, you have do a little parsing, methinks. Read the input as a string, then determine if it is a number or a letter. If it is a letter, that is easy, you just use it. If it is a number, you then convert it to the number value, e.g., by using strtol() (which can actually be used to determine if the input is a number).
    Thanks! Can you give me an example of how to use strtol().

  6. #6
    DESTINY BEN10's Avatar
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    HOPE YOU UNDERSTAND.......

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  7. #7
    Registered User georgio777's Avatar
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    Quote Originally Posted by BEN10 View Post
    Thanks!

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