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11-10-2009, 06:05 AM
| #1 |
| Registered User Join Date: Nov 2009
Posts: 6
| help in this code Code:
#include<stdio.h>
#include<conio.h>
#define N 50
void main()
{
char str[N+1]="aabccbbdds";
char ch;
int i=0;
int count[26]={0};
clrscr();
while((ch=str[i])!='\0')
{
count[ch-'a']++;
i++;
}
for(i=0;i<26;i++)
{
if(count[i])
{
printf("%c %d \n",i+'a',count[i]);
}
}
getch();
}
/* out put*/ a 2 b 3 c 2 d 2 s 1 /* but i want it should only give me repeating character and its frequency and in next line it should show me the those char which are non repeating one*/ can you help me plzzzzzz |
| nikki86 is offline |  |
|
11-10-2009, 06:12 AM
| #2 |
| Registered User Join Date: Oct 2009 Location: While(1)
Posts: 316
| Did u run your code the output you want is coming from your code miss |
| RockyMarrone is offline | |
|
11-10-2009, 06:18 AM
| #3 |
| Registered User Join Date: Oct 2009 Location: While(1)
Posts: 316
| And one more thing please use int main instead of void main as in C and in C++ always return type of main is int because we have to tell the system the execution status of the program |
| RockyMarrone is offline | |
|
11-10-2009, 06:49 AM
| #4 |
| Registered User Join Date: Nov 2009
Posts: 6
| yes i did run the code.. and this was the output |
| nikki86 is offline | |
|
11-10-2009, 06:52 AM
| #5 | |
| Registered User Join Date: Oct 2009 Location: While(1)
Posts: 316
| Quote:
Code: #include<stdio.h>
#define N 50
void main()
{
char str[N+1]="aabccbbdds";
char ch;
int i=0;
int count[26]={0};
while((ch=str[i])!='\0')
{
count[ch-'a']++;
i++;
}
for(i=0;i<26;i++)
{
#if 0
if(count[i])
{
printf("%c %d \n",i+'a',count[i]);
}
#else
printf("%c %d \n",i+'a',count[i]);
#endif
}
}
| |
| RockyMarrone is offline | |
|
11-12-2009, 07:50 AM
| #6 |
| Registered User Join Date: Nov 2009
Posts: 6
| not working properly please help need this not able to figure it out... thank you in advance what i want is if i enter a string BIOINFORMATICS the output should be:: non repeated characters are:: BNFRMATCS repeated charaters are:: I 3 O 2 Last edited by nikki86; 11-13-2009 at 06:17 AM. |
| nikki86 is offline | |
|
11-13-2009, 06:18 AM
| #7 | |
| Registered User Join Date: Nov 2009
Posts: 6
| help urgent Quote:
| |
| nikki86 is offline | |
|
11-13-2009, 06:47 AM
| #8 |
| Registered User Join Date: Oct 2009 Location: While(1)
Posts: 316
| i think first of all you should create another thread for another question and please first try out yourself |
| RockyMarrone is offline | |
|
11-13-2009, 09:44 PM
| #9 | |
| Registered User Join Date: Nov 2009
Posts: 6
| Quote:
Code:
#include<stdio.h>
#define N 50
void main()
{
char str[N+1]="BIOINFORMATICS";
char ch;
int i=0;
int count[26]={0};
while((ch=str[i])!='\0')
{
count[ch-'a']++;
i++;
}
for(i=0;i<26;i++)
{
if(count[i])
{
printf("%c %d \n",i+'a',count[i]);
}
else
{
printf("%c %d \n",i+'a',count[i]);
{
}
}
No this was the same question for this code ..... I DONT WANT THE OUTPUT THIS CODE IS GIVING...... INSTEAD I WANT TO GET OUTPUT AS I HAVE GIVEN IN QUOTE | |
| nikki86 is offline | |
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