help simple string outputting

This is a discussion on help simple string outputting within the C Programming forums, part of the General Programming Boards category; Can anyone help me, we have this assignment. A program that will ask for the full name (first name and ...

  1. #1
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    help simple string outputting

    Can anyone help me, we have this assignment. A program that will ask for the full name (first name and last name) and the birthday. then the program will output the first letter of full name and last name in capital.

    ex.

    Input name: dante lopez
    Your name is Dante Lopez

    I have a problem in making the first letter of the last name into upper case.

    Here is my C code:

    Code:
    #include <stdio.h>
    #include <conio.h>
    #include <string.h>
    #include <ctype.h>
    
    void main()
    {
    
    int x=0, mm,dd,yyyy,ctr,i,count;
    char name[25],choice;
    clrscr();
    
    puts("Input your name: ");
    gets(name);
    count=strlen(name);
    
    //name[25]=tolower(name[25]);
    name[0]=toupper(name[0]);
    
    for(x=0;name[x]<=count;x++)
    {
    i = isspace (name[x]);
    if(i==1)
    name[x++]=toupper(name[x++]);
    }
    
    printf("Input your birthday [mm/dd/yyyy]: ");
    scanf("%d/%d/%d",&mm,&dd,&yyyy);
    printf("\n\n");
    puts(name);
    
    if(mm==01)
    printf("January %d %d",dd,yyyy);
    else if(mm==02)
    printf("February %d %d",dd,yyyy);
    else if(mm==03)
    printf("March %d %d",dd,yyyy);
    else if(mm==04)
    printf("April %d %d",dd,yyyy);
    else if(mm==05)
    printf("May %d %d",dd,yyyy);
    else if(mm==06)
    printf("June %d %d",dd,yyyy);
    else if(mm==07)
    printf("July %d %d",dd,yyyy);
    else if(mm== 8)
    printf("August %d %d",dd,yyyy);
    else if(mm== 9)
    printf("September %d %d",dd,yyyy);
    else if(mm==10)
    printf("October %d %d",dd,yyyy);
    else if(mm==11)
    printf("November %d %d",dd,yyyy);
    else if(mm==12)
    printf("December %d %d",dd,yyyy);
    else
    printf("Month should be 1-12");
    
    printf("\n\nWould still like to input [y/n]: ");
    scanf("%s",&choice);
    
    getch();
    }
    Hope someone can help me...

  2. #2
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    OK, what will you always have to help mark the second name?

    How about a space - as in the space between the first and second name. And we know that the first letter after the space, will be the very letter that you want to capitalize.

    So, use strchr() to find the first space, and then increment the pointer one time, and then capitalize that letter with toupper().

    Or, you can scan through the name, from 0 to the index whose element in the array holds the space value (' '), or 32 - either one it's the same.

    So whichever way you want to do it, it will be done in approximately the same way.

  3. #3
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    @Adak

    thanks for the reply. Yes the space is the identifier for the last name. how will i use the strchr(), where will i put it? sorry i'm only new to this C language.

    Thanks.

  4. #4
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    If you're new than you want to do it yourself, just to get the experience:

    in a for loop, let's walk through the char array:

    Code:
    for(i = 0; yourArray[i] != 32; i++);
    
    //Note the semi-colon on the end - this is generally *wrong*, but this for loop needs
    //to do nothing else, for us.
    Now yourArray[i] is your space between names, so capitalize the yourArray[i+1], and you're on to the next problem.

    Because of differences in compilers and computers, yourArray[i] may have gone one too far, and already be at the first letter of the last name. Just FYI.

  5. #5
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    I can't seem to understand the strchr(). I'm having trouble in this string manipulation, can you please fix my loop part in my code.

  6. #6
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    @Adak

    I've changed my loop part into this:
    Code:
    for(x=0;name[x]!=' ';x++)
    {
    if(name[x]==' ')
    name[x+1]=toupper(name[x+1]);
    }
    Still no luck

  7. #7
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    Can somebody help me please....

  8. #8
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    Quote Originally Posted by kingdm View Post
    @Adak

    I've changed my loop part into this:
    Code:
    for(x=0;name[x]!=' ';x++)
    {
    if(name[x]==' ')
    name[x+1]=toupper(name[x+1]);
    }
    Still no luck
    You can't change the for loop logic around, and say "no luck". I gave you the logic, and the code - just use it, as I gave it to you.

    Here's an example, in a program.
    Code:
    #include <stdio.h>
    #include <ctype.h>
    
    int main(void) {
      char name[25] = "samuel adams";
      int i;
    
      for(i = 0; name[i] != 32; i++);
    
      name[0] = toupper(name[0]);
      name[i] = toupper(name[++i]);
      
      printf("\n\n %s", name);
    
      printf("\n\n\t\t\t     press enter when ready");
      i = getchar();
      return 0;
    }

  9. #9
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    Code:
    /* Get a pointer to the location of the space character */
    char *ptr = strchr(name, ' ');
    
    /* Make sure you actually found a space character */
    if (ptr != NULL)
       ptr[1] = toupper(ptr[1]);
    Keep in mind that this
    Code:
    for(i = 0; name[i] != 32; i++);
    is dangerous if the input string doesn't have a space character in it.

  10. #10
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    Then you could add:

    Code:
    for(i = 0; name[i] != ' ' && i < sizeof(name); i++);
    Assuming name is an array of chars, if the array size is defined as a constant sizeof() could be replaced with that.
    Last edited by Subsonics; 11-08-2009 at 01:04 PM.

  11. #11
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    Thanks a lot to all who replied, got the program working. Adak thanks a lot.

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