help with xrater case

This is a discussion on help with xrater case within the C Programming forums, part of the General Programming Boards category; Pls how can I make this to not differentiate between upper and lower cases? Code: #include <stdio.h> #include <string.h> int ...

  1. #1
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    Join Date
    Sep 2009
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    6

    help with xrater case

    Pls how can I make this to not differentiate between upper and lower cases?


    Code:
    #include <stdio.h>
    #include <string.h>
    
    int main()
    {
       int   occurrenceCount = 0;
       char   *searchPtr;
       char string[ 400 ];
       char tempStr[ 150 ];
       int numLines;
       int i;
       char key;
    
       printf( "Number of lines to be inputted: " );
       scanf( "%d", &numLines );
    
    	gets( tempStr );
    
       for ( i = 0; i < numLines; i++ ) {
          printf( "Enter string: " );
          gets( tempStr );
          strcat( string, tempStr );
       }
    
       printf( "Enter search character: " );
       scanf( "%c", &key );
    
       searchPtr = strchr( string, key );
    
       while ( searchPtr != NULL ) {
          ++occurrenceCount;
          searchPtr = strchr( searchPtr + 1, key );
       }
    
       printf( "\n\nTotal of occurrence character \'%c\' appeared in line(s) entered: %d\n\n",
               key, occurrenceCount );
    
       system( "PAUSE" );
       return 0;
    }

  2. #2
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    Sep 2006
    Posts
    8,868
    You can explicitly program it that way, or you can use toupper() or tolower() to set an entire string to either upper or lower case, as you wish.

    An example of explicit code is:

    Code:
    char choice;
    
    scanf("%c", &choice);
    
    if(choice == 'Y' || choice == 'y')
      //do something, knowing that either case is handled for 
      // the variable named choice

  3. #3
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    Join Date
    Sep 2009
    Posts
    6
    why cant I use scanf for to collect the input? when I try this it skips to the end of the program after asking for number of lines to be inputted.

    i.e.

    Code:
      printf( "Number of lines to be inputted: " );
       scanf( "%d", &numLines );
    
    	scanf("%[^\n]", tempStr );
    
       for ( i = 0; i < numLines; i++ ) {
          printf( "Enter string: " );
          scanf("%[^\n]", tempStr );
          strcat( string, tempStr );
       }

  4. #4
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    Sep 2006
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    8,868
    The key thing to remember with scanf(), is that you have to be aware of the keyboard buffer, *AT* the time you the program arrives at the scanf() line of code.

    So after scanf() is used once, there will be one (at least) newline char \n, in the keyboard buffer.

    The best way to clean up the keyboard buffer, is to just pull all the char's off it. Normally, that should just be one newline char, so one

    getchar();

    will be enough. If you have multiple scanf()'s, you should have a getchar() after every one of them that is followed by a scanf() for a char or string.

    scanf()'s for numbers are OK, since, when scanf() is looking for a number, it will pull off newline char's, and keep on going, looking for a number.

    But for char's, it can't do that, because the newline char itself *IS* a char. So it has to take it and say "OK, I got what I came for", and exit.

    Making it seem as though scanf() has skipped over the whole line - but it didn't.

    So:

    Code:
    scanf("%d", myNumber);   //ok, it's the first scanf(), so no newline is in the keyboard buffer
    
    scanf("%d", myNumber);  //ok, scanf() jumps over the newline in the buffer
    
    scanf("%c", myChar); //not okay, put a getchar() before this line of code.
    If you have a [^] format command that works with your compiler's scanf() - fine, use it. If not, use getchar() as needed.

    Hope that helps.

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