help with array and reminder.

[casper87]

hi guys. 2 quick questions!

1st:

i want to make a simple array that is unlimited and that takes all the numbers u put in it and prints the summary of em.


2nd:

how do i print the wggs that dont fit in the Containers? lets say i type in 28eggs. then i want to print :

you have; 28eggs
you need 2 containers
you have 4 eggs left.
fought i should use %reminder but didnt seem to get it to work

#include <stdio.h>
void main()
{ int iEgg, iContainer ,iLeft;

printf("type your amount of eggs: ");
scanf("%d", &iEgg);
ikartonger = iEgg / 12;


printf("you have: %d  Eggs\n", iEgg);
printf("you need: = %d containers\n",  iContainer);


iLeft =   ;
printf("you have: = %d eggs left\n", iLeft);
 }

[Adak]

#include <stdio.h>

void main()
{ int iEgg, iContainer ,iLeft;

printf("type your amount of eggs: ");
scanf("%d", &iEgg);
ikartonger = iEgg / 12;


printf("you have: %d  Eggs\n", iEgg);
printf("you need: = %d containers\n",  iContainer);


iLeft =   ;
printf("you have: = %d eggs left\n", iLeft);
 }

//c'mon Casper! You left "iLeft being assigned the value of <nothing>!!


iLeft = iEgg  - (iContainer * number in each container)

or

iLeft = iEgg % (iContainer * number in each container)

There's no such thing as "unlimited" in your computer. Everything is finite, especially arrays and RAM.

Printing up a summary should be no problem with any array. What have you tried ?

[casper87]

#include <stdio.h>

void main()
{ int iEgg, iContainer ,iLeft;

printf("type your amount of eggs: ");
scanf("%d", &iEgg);
ikartonger = iEgg / 12;


printf("you have: %d  Eggs\n", iEgg);
printf("you need: = %d containers\n",  iContainer);


iLeft =   ;
printf("you have: = %d eggs left\n", iLeft);
 }

//c'mon Casper! You left "iLeft being assigned the value of <nothing>!!


iLeft = iEgg  - (iContainer * number in each container)

or

iLeft = iEgg % (iContainer * number in each container)

There's no such thing as "unlimited" in your computer. Everything is finite, especially arrays and RAM.

Printing up a summary should be no problem with any array. What have you tried ?

yeah i did leave it empty, beacuse i dint know what to type

i dont understand what u mean with :

iLeft = iEgg - (iContainer * number in each container)

or

iLeft = iEgg % (iContainer * number in each container)

i did try to print the eggs that didnt fit in the containers by trying this code:

iLeft =   iEgg % Container

but it dint work..

the funny thing is when i try to use %reminder with nummbers it gives med the right answer. Like 17%5 = 2..



to be honest i think my brain is taking a break atm, becuse i cant think at all. cant get the structure at all...



this is my "unlimited array code so far:

 #include <stdio.h>
void main()
{

int iNumber[];
int sum;
for (int i=0;i<10; i++)
{

printf("put in numbers: ");
scanf("%d", &iNumber[i]);
sum += iNumber[i];
}
printf("%d", sum);

}

The fought is to make it work so that u can type in numbers until u press any other key, then the program take all the numbers and prints the sum of em.

[Adak]

Say you had 26 eggs:

You fill two containers, which each hold 12 eggs.

that would be 2 * 12 (containers * number each container holds)

Which totals to 24 eggs in containers.

Left over eggs = original number of eggs - eggs you put into containers, or

left over eggs = 26 - 24

left over eggs = 2

Which is a long way around to this answer:

left over eggs = 26 - (2 * 12)

You can't create an array with no size, unless you give the compiler a number it can could up for you. for instance, this is OK:

char myString[] = { "My Grandfather's clock was too large for the shelf, so it stood 90 years on the floor" };

And you don't have to count up all the char's for the array's size, the compiler will do it for you.

But if you just have
char myString[]

You have an array with no space, and should have a compiler warning at least.

If you put the above phrase into it, it should crash the program, before long.

[casper87]

Say you had 26 eggs:

You fill two containers, which each hold 12 eggs.

that would be 2 * 12 (containers * number each container holds)

Which totals to 24 eggs in containers.

Left over eggs = original number of eggs - eggs you put into containers, or

left over eggs = 26 - 24

left over eggs = 2

Which is a long way around to this answer:

left over eggs = 26 - (2 * 12)

You can't create an array with no size, unless you give the compiler a number it can could up for you. for instance, this is OK:

char myString[] = { "My Grandfather's clock was too large for the shelf, so it stood 90 years on the floor" };

And you don't have to count up all the char's for the array's size, the compiler will do it for you.

But if you just have
char myString[]

You have an array with no space, and should have a compiler warning at least.

If you put the above phrase into it, it should crash the program, before long.

think i sorted it out

#include <stdio.h>

void main()
{ int iEgg, iContainer ,iLeft , iSpace , iContainerhold;

printf("type your amount of eggs: ");
scanf("%d", &iEgg);
iSpace =12;
iContainerhold = iSpace;
iContainer =iEgg/iContainerhold;





printf("you have: %d  Eggs\n", iEgg);
printf("you need: = %d containers\n",  iContainer);


iLeft = iEgg - (iContainer* iContainerhold);
printf("you have: = %d eggs left\n", iLeft);
 }

u think u could code the unlimited" code for me? i reallt cant think right now..

[Adak]

Nope, because

1) I'm off for some breakfast and

2) You have it done, already. Give the array a size, and I believe you're set.

3) When you're ready, you need the practice. Programming is not a spectator sport, you have to really work at it.

Like most things, I guess.