Thread: Need Help With Putting Array in columns! any help will be appreciated!

Loop is a good idea. Ask yourself this question: after which elements do you want to print a new line? What is common about all those numbers?

Originally Posted by tabstop

Loop is a good idea. Ask yourself this question: after which elements do you want to print a new line? What is common about all those numbers?

here's what i'm trying to go with...but it prints out blank rows and columns

Code:

void myPrint(int x[], int size)
{
	int Print[25][4],i,j;

	for(i=0; i < size; i++)
	{
		for(j = 0; j < 4; j++)
		{
			Print[i][j] = x[i];
			printf("\n");
		}
	}
		

	
}

Thank you for the welcome Adak...yah i just started this 8 week advanced C course...and it was a year ago when i took the basic C course so i'm kind of losing it aha.

Size should be the number of rows, as you've coded it up, here. (outer loop represents the rows, inner loop represents the columns in a row).

Since you haven't put anything inside Print[][] array, I'm not sure you'll get much out.

Don't you want to do something with x[]?

You don't code in C frequently, you lose it, C? I know the feeling, believe me.

Originally Posted by tabstop

Loop is a good idea. Ask yourself this question: after which elements do you want to print a new line? What is common about all those numbers?

so i want to print a new line after the 4th element in each row...and the only thing in common about those numbers are that they were all scanned into my array myList.

Originally Posted by Adak

Size should be the number of rows, as you've coded it up, here. (outer loop represents the rows, inner loop represents the columns in a row).

Since you haven't put anything inside Print[][] array, I'm not sure you'll get much out.

Don't you want to do something with x[]?

You don't code in C frequently, you lose it, C? I know the feeling, believe me.

lol good point okay...so this was my next attempt.

Code:

void myPrint(int x[], int size)
{
	int i,j;

	for(i=0; i < size; i++)
	{
		for(j=0; j<4; j++)

			printf("%d\n", x[i]);
		
	}
		

	
}

and its printing in one single column now and printing every input 4 times lol arrrrghhh

Originally Posted by Ol_denjin

so i want to print a new line after the 4th element in each row...and the only thing in common about those numbers are that they were all scanned into my array myList.

Now you'll get the math heads all grumpy!

Some numbers are even, some numbers are odd, some are prime, some are "happy".

some are evenly divisible by 4.

You're trying to print a 1D array, like it was a 2D array. Remove the inner loop, for 1D arrays.

lol grumpy mathheads

sound like a prof. i used to have

I still recall my geometry teacher - we called him "Mad Dog Cameron".

He'd get on a roll, and he was the original (and real) "foamer"!

aha...that sounds terrifying!

just getting one single columnn...i know i'm missing something simple

Code:

void myPrint(int x[], int size)
{
	int i;
	


	for(i=0; i < size; i++)
	{
		
			printf("%d", x[i]);
		printf("\n");
		
	}
		

	
}