Thread: Odd or even

Are you saying I should put in an if statement? And which "return" are you wanting me to look at?

Ok, all that is doing is determining what the remainder is and printing it out. And the reason it is not printing "10 is even" is because I have not told it how to print out even.

Originally Posted by BB89

Ok, did some work but still doesnt workout.

My output is

10 is 1
11 is 0
.
.
.
.
19 is 0
20 is 1

Code:

#include <stdio.h>

int even(int n) // return sum from 1 to n
{
    return ( n % 2 == 0 );
}

int main (void)
{
    int i, sum;

    for (i = 10; i <= 20 ; i++)
    {
        sum = even(i);
        printf("%d is %d\n", i, sum);
    }
    return 0;
}

How do I make it say 10 is even, 11 is odd, etc..?

i see what you mean

ok so the even function returns 1 for even number

and returns 0 for odd number.

so just put an if loop

Code:

 printf("%d is %d\n", i, sum);

sum --> gives either 1 or 0

best of luck

Ok, I put in an if statement but it is working but putting out an odd answer.

it is saying:

10 is 4even
11 is 5odd

Code:

#include <stdio.h>

int is_even(int n) // return sum from 1 to n
{
    if(n % 2 == 0)
        printf("odd\n");
    else
        printf("even\n");
}

int main (void)
{
    int i, sum;

    for (i = 10; i <= 20 ; i++)
    {
        sum = is_even(i);
        printf("%d is %d", i, sum);
    }
    return 0;
}

Originally Posted by BB89

Ok, I put in an if statement but it is working but putting out an odd answer.

it is saying:

10 is 4even
11 is 5odd

Code:

#include <stdio.h>

int is_even(int n) // return sum from 1 to n
{
    if(n % 2 == 0)
        printf("odd\n");
    else
        printf("even\n");
}

int main (void)
{
    int i, sum;

    for (i = 10; i <= 20 ; i++)
    {
        sum = is_even(i);
        printf("%d is %d", i, sum);
    }
    return 0;
}

ok almost there..but if you do that how will you retun either 1 or 0?.

try putting the if loop inside the main method ..

this loop explains by itself.

Code:

if(sum==1) 
{
  print number is even
}
else
   number is odd.

How would I use my function then?

Yes, I understand

This is what I dont understand

Code:

10 is 4even
11 is 5odd

What is the 4 in front of even and the 5 in front of odd?

Whoa horsey!!! Stop. Calm down. Now, here is what you need to do. WITHOUT WRITING ANY CODE tell us what you need to do and how you plan to do it. Programming is not about the language you are using. Who cares that you are doing this in C? Do you even know how to get this answer? What would you do if I asked you to PROVE that each number from 10 to 20 was odd or even? How would you do that? Write it down, post it here and let us see that you know what you are doing FIRST. Then, we can help you get your thoughts to code.

Currently, I don't think you have a handle on the problem.

Originally Posted by Obelisk

ok here

Code:

 printf("%d is %d", i, sum);

delete the 2nd %d and sum

do this

Code:

printf("%d is ", i);

If you listen to this, then you've done this project incorrectly.

Originally Posted by Kennedy

If you listen to this, then you've done this project incorrectly.

i know but the question he asked was why was the presence of 4even and 5odd i just

showed him how to remove it.

your almost there actually, with your permission i can show you the code if you want to

understand the logic