Thread: Loops forever

Hi.. I am doing C programming on microsoft Visual C++. I want to prompt the user for coordinate again and again if the input coordinate doesn't meet the condition. But after I type in the coordinate, the program keeps on looping infinitely. Sorry for the super BEGiNNER question.

Code:

#include <stdio.h>
#include <stdlib.h>
#include <math.h>

int main()
{

	int x,y,invalid=1;

	while (invalid)
	{
		printf("Please enter the coordinate of the ship:\n");
		scanf(" %d %d", &x,&y);

		invalid=((x>10 || x<0) &&(y<10 || y>25))?1:0;
	}
	
}

I want to prompt the user again for coordinates if the user types a coordinate within this range
(x>10 || x<0) &&(y<10 || y>25)

thanks for the detailed reply man.. I got it. My condition was wrong..

If it were me, I'd rather do something like this. The user gets feedback, and the code is easier to read and understand.

Code:

#include <stdio.h>
#include <stdlib.h>
#include <math.h>

int main()
{

	int x,y,invalid=1;

	while (invalid == 1)
	{
		printf("Please enter the coordinate of the ship:\n");
		scanf(" %d %d", &x,&y);

		if ((x>=0 && x<=10) && (y>=10 && y<=25)) {
			invalid = 0;
		} /* if ((x>=0 && x<=10) && (y>=10 && y<=25)) */
		else {
			printf("Invalid.\n");
			invalid = 1;
		}/* else */
	} /* while (invalid == 1) */
	
}/* main */

yours is much neater cosmic_cow.. I've another problem.

I need the x coordinate to be between 0 and 19, and the
y coordinate to be between 10 and 19.[As stated in the condition]

I tried entering a coordinate of (5,5). This is supposed to yield
a value of 1. then it's supposed to go through the while loop again but it's not looping! Can someone tell me why? thanks!

Code:

#include <stdio.h>
#include <stdlib.h>
#include <math.h>



int main()
{

	int x,y,i,j,A,invalid=1,rc;
	
	FILE* fw = fopen("status.txt", "r");
	FILE* fp = fopen("status.txt", "w");
	
	/*Creating a text file which has 20 rows of 20 zeroes*/
	for(i=0;i<20;i++)
	{
		for(j=0;j<20;j++)
			fprintf(fp,"%d ", 0);
		fprintf(fp,"\n");
	}
	fclose(fp);
	

	while(invalid)
	{
		printf("Please enter the coordinate:\n");
		scanf(" %d %d", &x,&y);

		invalid=((x>0 && x<19) &&(y>10 && y<19))? 0: 1;
		printf("The value of invalid the first time is %d\n", invalid);
		A=20*y+x;
		if(invalid=0)
		{	
			/*Reading the status.txt file*/
			for (i=0;i<=A;i++)
			{
				fscanf(fw, "%d ", &rc);
			}	
			fclose(fw);
				if (rc==1)
					invalid=1;	
				else 
					invalid=0; 
		}
	}
	return 0;
}

Your program needs another variable, like int pair = 0, before the while loop starts.

Then, when you get your first pair, set the variable pair to 1. Inside the while loop, after invalid is set to 0, you need code something like:

Code:

//this should be placed so it runs ONLY when the 
//first set of coordinates is valid
if(pair == 0) {  //or if(!pair) {
  invalid = 1;
  pair = 1;
}

That will cause a second time through the while loop, and if your other logic is ok, the second set of coordinates can be assigned.

- You cannot open a file for "r" before even creating it. If the file exists, under unix, you may get results but not what you expected. If the file doesn't exist then 'fw' is NULL throughout execution and you have not checked for this. What's the point of this file anyway? Are we trying to do some sort of named pipe at this programming level?? Anyway do your "r" open after you've written the whole file and fclose()'d it when it gets flushed.

- I think you meant "if(invalid==0)" rather than "if(invalid=0)"?

- If you close 'fw' then it's not open for the next pass of the loop and stuff will fail. But again you haven't checked for that so you'd never see it.

gcc:32: Confused by earlier errors, giving up.

Thanks adak and core_cpp! Changing the if(invalid=0) to if(invalid==0) solved the problem. I am creating the status.txt first and then reading it..

Another small question.. what does the following statement mean? invalid and val are variables..
Thanks..
invalid = invalid?1:val?1:0;