Thread: Simple division program help

Well the 'digit' depends on the number base, but I'm assuming you mean the decimal representation? In that case, you can extract the digit (D) by obtaining the modulo of the number (N) with 10. Run the even/odd test on D, increment the appropriate counters, and then divide N by 10 and repeat the process, until N is zero.

int XXX;
int aa;
int bb;
int cc;

printf( "Please enter a number: " );
scanf( "%d", &XXX );

aa = XXX / 100;
bb = XXX / 10 - aa * 10;
cc = XXX - aa * 100 - bb * 10;

Okay i seem to have succeded in isolating each digit even though I'm sure there's a simpler way than what i did, now i'm going to work on adding them up in the right way.

First of all, variable names like 'XXX' and 'aa' are not very informative. The more descriptive, the less comments you have to write to explain what each variable does. Anyway, you need a loop. Here's some pseudocode:

Code:

Read input into VALUE
Loop:
    Set DIGIT to VALUE modulo BASE.
    Test DIGIT for evenness. If so, increment EVEN counter, otherwise ODD.
    Divide VALUE by base. If the result is zero, break out of loop.

I'm not good enough at c to even understand what you mean.

Code:

#include <stdio.h>

int main()
{
  int XXX;
  int aa;
  int bb;
  int cc;




  printf( "Please enter a number: " );
  scanf( "%d", &XXX );

   aa = XXX / 100;
   bb = XXX / 10 - aa * 10;
   cc = XXX - aa * 100 - bb * 10;

   if (aa % 2 == 0 && bb % 2 == 0 && cc % 2 == 1 && aa + bb - cc == 0);
       printf ("yes");

   else if (aa % 2 == 0 && bb % 2 == 1 && cc % 2 == 1 && aa - bb - cc == 0);
        printf ("yes");

   else if (aa % 2 == 1 && bb % 2 == 0 && cc % 2 == 1 && aa - bb + cc == 0);
      printf ("yes");

   else if (aa % 2 == 1 && bb % 2 == 1 && cc % 2 == 0 && aa + bb - cc == 0);
       printf ("yes");

    else if (aa % 2 == 1 && bb % 2 == 0 && cc % 2 == 0 && aa - bb - cc == 0);
        printf ("yes");

    else if (aa % 2 == 0 && bb % 2 == 1 && cc % 2 == 0 && aa - bb + cc == 0);
       printf ("yes");




   else printf ("no"};




  return 0;
}

Anyway here's what I came up with, it's a code which answers yes when the sum of the odd digits equals the sum of the even digits in a number (in this code 3 digit and less numbers).

My problem is that I get an error saying "syntax eror before else", please help me.

Thanks it's up and working.