I have a programming assignment, and I am really struggling with it. I am supposed to produce a conversion table, that converts British pounds to US dollars. The program should first allow the user to enter an exchange rate. Then the program should print conversions for amounts beginning with one pound, in .25 increments, for amounts less than twenty pounds. Formatting should be the same as the sample output shown:
Enter exchange rate (GBP/USD): 1.6471
P 1.00 = $ 1.65 P 1.25 = $ 2.06 P 1.50 = $ 2.47 P 1.75 = $ 2.88
P 2.00 = $ 3.29 P 2.25 = $ 3.71 P 2.50 = $ 4.12 P 2.75 = $ 4.53
P 3.00 = $ 4.94 P 3.25 = $ 5.35 P 3.50 = $ 5.76 P 3.75 = $ 6.18
P 4.00 = $ 6.59 P 4.25 = $ 7.00 P 4.50 = $ 7.41 P 4.75 = $ 7.82
P 5.00 = $ 8.24 P 5.25 = $ 8.65 P 5.50 = $ 9.06 P 5.75 = $ 9.47
P 6.00 = $ 9.88 P 6.25 = $10.29 P 6.50 = $10.71 P 6.75 = $11.12
P 7.00 = $11.53 P 7.25 = $11.94 P 7.50 = $12.35 P 7.75 = $12.77
P 8.00 = $13.18 P 8.25 = $13.59 P 8.50 = $14.00 P 8.75 = $14.41
P 9.00 = $14.82 P 9.25 = $15.24 P 9.50 = $15.65 P 9.75 = $16.06
P10.00 = $16.47 P10.25 = $16.88 P10.50 = $17.29 P10.75 = $17.71
P11.00 = $18.12 P11.25 = $18.53 P11.50 = $18.94 P11.75 = $19.35
P12.00 = $19.77 P12.25 = $20.18 P12.50 = $20.59 P12.75 = $21.00
P13.00 = $21.41 P13.25 = $21.82 P13.50 = $22.24 P13.75 = $22.65
P14.00 = $23.06 P14.25 = $23.47 P14.50 = $23.88 P14.75 = $24.29
P15.00 = $24.71 P15.25 = $25.12 P15.50 = $25.53 P15.75 = $25.94
P16.00 = $26.35 P16.25 = $26.77 P16.50 = $27.18 P16.75 = $27.59
P17.00 = $28.00 P17.25 = $28.41 P17.50 = $28.82 P17.75 = $29.24
P18.00 = $29.65 P18.25 = $30.06 P18.50 = $30.47 P18.75 = $30.88
P19.00 = $31.29 P19.25 = $31.71 P19.50 = $32.12 P19.75 = $32.53 [/B]
I must use a double and int. Also, I must have 2 nested loops involved.
So far I have:
#include <stdio.h>
int main (void)
char Dollars;
char Pounds;
printf ("Enter Exhange Rate (GPS/USD): %d/n");
This is where I got lost, in relation to nested loops and such. Someone's help would be deeply appreciated.
