problem: char string[j] in if statement

[lye85]

#include <stdio.h>
#include <string.h>

void main()
{

	
	char string[200]="int main() { int x=10; int y=5; if (x==10) { printf('hello'); } else {;} }";
		
	int count;
	count = strlen(string);
	printf("%d\n",count);

	int parentheses = 0;
	
	for(int j=0; j<count; j++){
		if(string[j] == 'x'){
		parentheses++;
		}	
                }

	printf("%d",parentheses);

	
}

the lenght of string[200] is 74, variable parentheses is used to determine how many 'x' in string, but "if(string[j] == 'x')" always true, parentheses is 74 after a for loop finish, can some one correct me?

[MK27]

The output of this code is correct, there are

2

so what is the problem?

[Kennedy]

One thing that scares me about that is the

for (int j = 0; j < count ; j++)

but that is because I don't like the C99 (c++ type) declarations. . . though I don' t think that is the problem. Are you sure that you have an == where you have it up there?

[nonoob]

Maybe you wanted to be counting parenthesis and not 'x'.