No, that part of the code appears to be correct. What is happening is that prev is stepping through the linked list as it is being built. prev = current fixes that.
No, that part of the code appears to be correct. What is happening is that prev is stepping through the linked list as it is being built. prev = current fixes that.
i know thats logical but whats puzzling me is we now allocating memory right in this loop iteration so when we allocate by malloc that memory gets passed to both prev and current i tried to remove prev it didnt work coz prev points to previous member i think but what i dont understand is how it works ....
k ic but when memory is allocated now wouldnt at end of the loop prev=current; and remove the else and code would work aswell ? since we assigned ptrs then all stuff inside are = ?Originally Posted by Kennedy
yes yes i c i understand it now i just didnt concentrate well on the test lol
on first time it wont enter the tests but the perv will keep track by setting perv to current i feel so stupid lol
so basically here first time loop runs perv gets assigned to current then after that on 2nd time when loops runs it sets perv->next which sets perv->next to previous next of current right ?
