Does anyone know how to do an array of function pointers when its double array?.
fip.c:1: error: expected expression before ‘,’ tokenCode:FIPFunc[ , ] = {&FIPDiscSolicit(), &FIPDiscAdv(); &FIPReq(), &FIPACC(); &FIPKeAlive(), &FIPViLinks(); &FIPVLANReq(), &FIPVLANNot(); };
I'm pretty sure Im declaring this wrong but All the tutorials online aren't really sure how to do it for double array function pointers
Well you don't use , to specify that you have two dimensions. You actually specify two dimensions...You aren't doing that.Code:int array[ SOMENUMBER ][ SOMEOTHERNUMBER ];
Quzah.
Hope is the first step on the road to disappointment.
Also keep in mind that only one dimension can be unspecified, so foo[ ][ ] is invalid.
Okay so i put
But I get a lot ofCode:int FIPFunc[2][4] = {&FIPDiscSolicit(), &FIPDiscAdv(), &FIPReq(), &FIPACC(), &FIPKeAlive(), &FIPViLinks(), &FIPVLANReq(), &FIPVLANNot() };
error: lvalue required as unary ‘&’ operand
What does that mean should i not use the & sign
The name of a function is a pointer to that function (in almost all cases). You should not use () to "remind" the compiler that it's a function, as the compiler already knows that. What you're doing is attempting a function call and applying the & operator to the result. Just use the function name without parentheses. Optionally you can add an & if you think it makes semantic sense.
Don't really know what an array of int has to do with an array of pointers. Don't you want something like this:
If the functions don't return the same type and have the same parameters, still wouldn't you want an array of void*Code:typedef void (*fun)(int, int); fun arrayFun[2] = {thisFun, thatFun};
Code:void* arrayFun[2] = {thisFun, thatFun};
Yeah, probably <5 people (including the OP) in the history of the universe have felt the need to do such a thing, so surprise surprise there isn't a good "2D function pointer array How-to".Originally Posted by kiros88
C programming resources:
GNU C Function and Macro Index -- glibc reference manual
The C Book -- nice online learner guide
Current ISO draft standard
CCAN -- new CPAN like open source library repository
3 (different) GNU debugger tutorials: #1 -- #2 -- #3
cpwiki -- our wiki on sourceforge
Sorry about that i changed it in my code i was getting that error two I also wanted to know when u do a call for the array of functions pointers what do u get back like.
in this example whats in result2.... I got this from a website that didnt explain what the result2 is. Is it just like a status either returning -1 if failed or 1 if successfulCode:int result2 = (*pt2Function) (12, 'a', 'b'); // C
Well who knows? pt2Function sounds like "a name we needed to make up". It depends on what function was called, and what that function does/returns.
So basically the result2 is whatever each of the functions returns does that mean each function call in the array have to return the same type of data back?
A pointer to an array. I think the tutorial you were reading recommends typedef'ing, so it would be an array of a custom type. The typedef is a good idea; function ptr syntax is cumbersome.
Code:#include <stdio.h> typedef (*FPtr)(int); int test(int x) { return x; } int main() { FPtr eg[5]; int i,r2; for (i=0;i<5;i++) { eg[i] = test; r2 = eg[i](i); printf("%d\n",r2); } return 0; }Yes and yes, but you could use the flexible "void*".
C programming resources:
GNU C Function and Macro Index -- glibc reference manual
The C Book -- nice online learner guide
Current ISO draft standard
CCAN -- new CPAN like open source library repository
3 (different) GNU debugger tutorials: #1 -- #2 -- #3
cpwiki -- our wiki on sourceforge
Since there really isnt that many do u know any good ones to use im trying to call on it now and im getting an error
error: called object ‘FIPFunc[((unsigned int)hdr->Code, (unsigned int)hdr->Subcode)]’ is not a function
how do u call on the funtion pointer array isnce its 2-dCode:typedef struct FIP_Hdr { Uint32 Code:16; Uint32 Resv1:8; Uint32 Subcode:8; Uint32 DescLen:16; Uint32 DescList; } FIP_Hdr; Uint32 DescListLen; Uint8 *DescListPtr; DescListLen = (Uint32) hdr->DescLen; DescListPtr = (Uint8*)&(hdr->DescList); int status = (*FIPFunc[(Uint32) hdr->Code, (Uint32) hdr->Subcode])(DescListPtr, DescListLen);
This is not a 2-D function pointer array question. This is a 2-D array question. Just like every other 2-D array, you use a separate pair of brackets for each dimension, as in [4][3].
No, in fact I was being serious kiros88, I doubt very many people have ever wanted to do that, so you are sort of on your own.
But using the typedef, you should be able to do it. If you have not passed around arrays of pointers to arrays or 2d arrays much write a short demo using char *ptrs to get used to the syntax before you start in on the typedef function ptrs.
C programming resources:
GNU C Function and Macro Index -- glibc reference manual
The C Book -- nice online learner guide
Current ISO draft standard
CCAN -- new CPAN like open source library repository
3 (different) GNU debugger tutorials: #1 -- #2 -- #3
cpwiki -- our wiki on sourceforge
So i put that with the brackets in the right order but i still keep getting the errorCode:int status = (FIPFunc[(Uint32) hdr->Code] [(Uint32) hdr->Subcode])(DescListPtr, DescListLen);
error: called object ‘FIPFunc[(unsigned int)hdr->Code][(unsigned int)hdr->Subcode]’ is not a function
which its not a function cuz Its suppose to be an array?
