mean, mode median calculation..

This is a discussion on mean, mode median calculation.. within the C Programming forums, part of the General Programming Boards category; hey there.. this is my code... Code: #define SIZE 100 #include<stdio.h> float mean_function(float[],int); float median_function(float[],int); float mode_function(float[],int); int main() { ...

  1. #1
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    mean, mode median calculation..

    hey there..
    this is my code...

    Code:
    #define SIZE 100
    #include<stdio.h>
    float mean_function(float[],int);
    float median_function(float[],int);
    float mode_function(float[],int);
    int main()
    {
    int i,n,choice;
    float array[SIZE],mean,median,mode;
    printf("Enter No of Elements\n");
    scanf("%d",&n);
    printf("Enter Elements\n");
    for(i=0;i<n;i++)
    scanf("%f",&array[i]);
    do
    {
    printf("\n\tEnter Choice\n\t1.Mean\n\t2.Median\n\t3.Mode\n4.Exit");
    scanf("%d",&choice);
    switch(choice)
    {
    case 1: mean=mean_function(array,n);
    printf("\n\tMean = %f\n",mean);
    break;
    case 2: median=median_function(array,n);
    printf("\n\tMedian = %f\n",median);
    break;
    case 3: mode=mode_function(array,n);
    printf("\n\tMode = %f\n",mode);
    break;
    case 4: break;
    default:printf("Wrong Option");
    break;
    }
    }while(choice!=4);
    }
    
    /***************************************************************
    Function Name : mean_function
    Purpose : to find mean
    Input : array of elements,no of elements
    Return Value : Mean
    Return Type : Float
    ****************************************************************/
    float mean_function(float array[],int n)
    {
    int i;
    float sum=0;
    for(i=0;i<n;i++)
    sum=sum+array[i];
    return (sum/n);
    }
    
    /***************************************************************
    Function Name : median_function
    Purpose : to find median
    Input : array of elements,no of elements
    Return Value : Median
    Return Type : Float
    ****************************************************************/
    
    float median_function(float a[],int n)
    {
    float temp;
    int i,j;
    for(i=0;i<n;i++)
    for(j=i+1;j<n;j++)
    {
    if(a[i]>a[j])
    {
    temp=a[j];
    a[j]=a[i];
    a[i]=temp;
    }
    }
    if(n%2==0)
    return (a[n/2]+a[n/2-1])/2;
    else
    return a[n/2];
    }
    
    float mode_function(float a[],int n)
    {
    return (3*median_function(a,n)-2*mean_function(a,n));
    }

    i've got problem with "mode" formula..
    the program didn't give me the correct answer..
    should i use "sort()"?

  2. #2
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    Is this what you were trying for?
    In continuous unimodal distributions the median lies, as a rule of thumb, between the mean and the mode, about one third of the way going from mean to mode. In a formula, median ≈ (2 mean + mode)/3. This rule, due to Karl Pearson, is however not always true and the three statistics can appear in any order.[1] It often applies to slightly non-symmetric distributions that resemble a normal distribution.
    Since it "is not always true", I wouldn't use it for your program.

    I would set up your categories (the range of each), and then just count the instance of each in your data, using a simple integer array. Similar to a histogram.

    Wikipedia article mentions sorting in their article on mode (from which the above quote is taken), but I see no reason to sort the data to find the mode of your data.

  3. #3
    and the hat of wrongness Salem's Avatar
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    I dunno, 30+ posts, and still can't indent your way out of a wet paper bag.

    It's an unreadable mess that is going ignored!
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.
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