I have read at few places that it is not good to use fflush (stdin) as result may be undefined.
So what shall I use? Without this I am facing problems whenever i try to read a string from keyboard when I have read something before. I am using MinGW compiler.
Well, here is the explanation of why it is wrong(which I believe you know of already) -
Cprogramming.com FAQ > Why fflush(stdin) is wrong
and here is the solution -
Cprogramming.com FAQ > Flush the input buffer
Thanks a billion..
But what does the following line signify as given in the link u have given..
Code:while ((ch = getchar()) != '\n' && ch != EOF);
It just one by one pulls out any letters queued up in the input buffer until an EOL or EOF comes up.
Pardon.
EOL OR EOF as u have said. But in the statement it is written EOL AND EOF.
So please explain..
I didn't mean logically "OR" I mean semantically or. If an EOL comes up, the loop ends. If an EOF comes up, the loop ends.
More specifically, the opposite of or is and. You want to stop when you get EOL or EOF -- but you have to write the loop to say when you want to keep going.
this thread can help you as well.
Whenever a single item in an expression containing the logical && operator evaluates to false, no other comparisons are made and the result is false.while ((ch = getchar()) != '\n' && ch != EOF);
Pardon.
EOL OR EOF as u have said. But in the statement it is written EOL AND EOF.
So please explain..
So, if either EOL or EOF is reached, the statement will evaluate to false and stop further evaluation.
Loop while the fetched character is not '\n' AND the fetched character is not EOF.
So if the fetched character == '\n', what happens? The first condition is false, the second condition is true, but since it's AND, it must be false, right? So the loop breaks.
And if the fetched character == EOF, what happens? The first condition is true, the second condition is false, and since it's AND, it must be false again, right? So the loop breaks.
So we see that if either of the conditions (the left or right) in the loop becomes false, the loop breaks.
Originally Posted by Adak
You can google out "Truth Table" it'll help you understand it easily.
They mean "if c is not \n and c is not EOF". The same as "if c is neither \n nor EOF"
