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hey there.. need ur guys help here..
ok.. let me give u guys my question so that it will be clearer for u to help me.. =)
"Your program will prompt the userto enter a series of number and the last value
read is sentinel 999.(i.e to end input, the user must enter 999 as the last value"
how am i going to do this?
You will prompt the user to enter a series of numbers. You will then read numbers until a 999 is read.
Use scanf to read integers until you read 999.Quote:
Originally Posted by naspek
It is very simple...
It means all you do is write some pseudo code on how you would do this logically, then translate it into code.
No tricky C stuff or anything.
ok... i dont know how to use scanf to read the integers..Quote:
Originally Posted by BEN10
actually.. this is just part of the full code.. but, i just cant figure out, how to solve this problem..
it may look simple for an experience programmer, but, for newbie like me,
it's kinda hard..
please please please give me an example.. =)
scanf("%d", &myvar);
You can look at the documentation for scanf what parameters it accepts and what they mean.
Here's an example.Quote:
Originally Posted by naspek
Actually to read a list of numbers until 999, you will have to use a loop with the condition being num!=999.Code:int i;
printf("Enter i");
scanf("%d",&i);
You don't need to tell them how to do things logically. A programmer must be able to figure that out him-/herself.
Using loops and placing code in right positions are not solutions we should hand out.
Actually my aim was to tell the OP that if he/she doesn't know how to use scanf, then it might be difficult to do this problem.Quote:
Originally Posted by Elysia
Really? Then what was the purpose of the last bit?
Quote:
Originally Posted by BEN10
ok.. the program suppose to be like this..
Enter temperature readings in Fahrenheit (999 to end): 80 90 85
75 70 999
i dont know how to do the 999 at the last of the sentence..
Well, I'm assuming you've got the first part done since your posting it.
So, That means that you are reading in input and storing it somewhere right ?
So, all you have to do is think of a way to not read in more data if the user entered 999.
Try writing it in english and then work your way into code.
heres a simple example -
Ask the user for input.
Check the input.
If it is not 999, store it.
otherwise
stop asking for input.
Again I got misunderstood:eek:. Seriously I wasn't in a mood to provide the OP the solution to his/her query. Ok, now from the next time I'll be more cautious while posting.Quote:
Originally Posted by Elysia
Alright, no worries.
BEN10 - picture Elysia as a "watch hound" and what you did was equivalent to passing a note off during an exam!
She busted me once...or twice. No worries.
What would really get me is if the same OP, continued to post the same problem if after giving such guidance on how to write the code.
should i use "if... else....." to solve it?Quote:
Originally Posted by Spidey
Well, there are a number of ways you could solve this problem.Quote:
should i use "if... else....." to solve it?
My point was not to take it what I wrote as a direct translation, but to think about the problem and how you would solve it.
If you believe you could do it using an if..else statements then go ahead and try it out and see what you come up with. After that think of ways to improve your program or how you could write it using a different approach.
The best way to learn programing is by actually doing it, and I'm sure you've heard this/will hear this a lot of times.
So write some code and see where you get with it.
The very basic fundamentals for a programmer is to be able to code logic! This usually means that the programmer can translate flow charts and pseudo code into real code.
This is a part we cannot help you with! This is the part that YOU must fully understand in order to program any sort of program.
But it's not difficult. All that is required is that you think about how something is done and that you know about these control statements in the language.
Do you know about loops and if statements? They control the logic of the program.
thanks guys.. i'd try already.. but, got some errors...
can u guys help me.. just state wut is wrong..
i'll try to figure out myself, coz i wanna learn it.. =)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~Code:#include <stdio.h>
int main ()
{
float average, fahrenheit, Celcius, total;
int counter;
total = 0;
counter = 0;
do {
printf("Enter temperature readings in Fahrenheit (999 to end): ");
scanf("%f", &fahrenheit);
counter = counter + 1;
Celcius = (fahrenheit-32) * 5/9;
printf("\n%d.Fahrenheit\tCelsius\n", counter);
printf("%.2f\t\t%.2f\n\n", fahrenheit, Celcius);
}while (fahrenheit != 999);
if (counter != 0) {
total = total + Celcius;
average = total / counter;
printf("Average is %.2f Celcius\n", average);
}
else
printf("No reading is entered.\n");
return 0;
}
i want the output to be like this:
Enter temperature readings in Fahrenheit (999 to end): 88 77 80 999
1. Fahrenheit-------Celcius
88-------------------30.89
2.Fahrenheit--------Celcius \*please ignore "-----------" i just want to make the output*\
77--------------------24.77
3.Fahrenheit--------Celcius
80--------------------26.67
Average 41.65 Celcius
but, my 'else" isnt workin...Code:#include <stdio.h>
int main ()
{
float average, fahrenheit, Celcius, total;
int counter;
total = 0;
counter = 0;
printf("Enter temperature readings in Fahrenheit (999 to end): ");
scanf("%f", &fahrenheit);
while (fahrenheit != 999)
{
Celcius = (fahrenheit-32) * 5/9;
total = total + Celcius;
counter = counter + 1;
printf("\n%d.Fahrenheit\tCelsius\n", counter);
printf("%.2f\t\t%.2f\n\n", fahrenheit, Celcius);
scanf("%f", &fahrenheit);
}
if (counter != 0) {
average = total / counter;
printf("Average is %.2f Celcius\n", average);
}
else
printf("No reading is entered.\n");
return 0;
}
how can i fix it?
In what way does it not work?
ok~Quote:
Originally Posted by tabstop
the program should exit to else statement if i enter the input without 999..
but it doesnt go to else statement....
Code:Enter temperature readings in Fahrenheit (999 to end): 77
1.Fahrenheit Celsius
77.00 25.00
You have no if, let alone an else, inside your while loop.
ah ha!! got it tabstop!! gee~ thanks!Quote:
Originally Posted by tabstop