^power

[xlordt]

i have created a simple calc but how can i make it calculate
3^5 using switch and case... well anywayz just in case here is my code

#include <stdio.h>
#include <math.h>

int main()

{
int x,y;
char var;



printf("Type the operator +,-,/,* and your prob in this format 5+5\n");
scanf("%d%c%d",&x,&var,&y);
switch(var)
{
case '+':
printf("Answer = %d\n",x+y);
break;
case '/':
printf("Answer = %d\n", x/y);
break;
case '-':
printf("Answer = %d\n", x-y);
break;
case '*':
printf("Answer = %d\n", x*y);
break;
case '^':
printf("Answer = %d\n", x^y);
break;
default:
printf(" please try that again\n ");
system("./a.out");
}
}

[adrianxw]

Look up the pow() function in the help.

[xlordt]

the calc is being created in linux.. sorry..

[Magos]

This is probably not an efficient way to do this, but anyway:

int Result=1;
for(int i=0; i<y; i++)
{
  Result*=x;
}

Assuming x and y is the same as in your code, and y is never less than 0.

[xlordt]

ya i need it with case... if i do it like that then i will have to redo my code in somewayz

[adrianxw]

>>>
if i do it like that then i will have to redo my code in somewayz
<<<

Your going to have to redo it anyway as what you've got doesn't work!

If you haven't got a power function, (I can't believe Linux does not have a power function, I don't know what it would be called, but it is there somewhere), then you're going to have to calculate it aren't you.

[Magos]

Originally posted by xlordt
ya i need it with case... if i do it like that then i will have to redo my code in somewayz

Not that much:

case '^':
  for(int i=0; i<y; i++)
  {
    Result*=x;
  }
  printf("Answer = %d\n", Result);
break;

[xlordt]

i keep getting a pars error in int... how can i fix thiz

[Govtcheez]

That's because in C, you have to declare your variables before everything else. Put the int i = 0; with your other variable declarations.