Code:Here is the program description: 1. Write a grading program for a class with the following grading policies. a. There are two quizzes, each graded on the basis of 10 points. b. There is one midterm exam and one final exam, each graded on the basis of 100 points. c. The final exam counts for 50% of the grade, the midterm counts for 25%, and the two quizzes together count for a total of 25% (Do not forget to normalize the quiz scores). The program will read in the students’ scores and output the student’s numeric score for the entire course. The program will display the average of the quizzes, tests, and the total score before it terminates. A session with the program might look like this: Enter the student's name: Mike Fisher Enter the student's grade for quiz #1: 8 Enter the student's grade for quiz #2: 9 Enter the student's grade for midterm: 89 Enter the student's grade for final: 98 Mike Fisher's numeric score for the entire course is 92.5 Would you like to enter another student record? y(yes) or n(no)?y Enter the student's name: Jon Stewart Enter the student's grade for quiz #1: 7 Enter the student's grade for quiz #2: 8 Enter the student's grade for midterm: 78 Enter the student's grade for final: 84 Jon Stewart's numeric score for the entire course is 80.25 Would you like to enter another student record? y(yes) or n(no)?n The average score on quiz1 is 7.5 The average score on quiz2 is 8.5 The average score on midterm is 83.5 The average score on final is 91 The average score for the entire course is 86.375 Specifications: 1. The program should be built around an array of structures, with each structure containing information of a student’s record, including name (a string), quiz 1 score, quiz 2 score, midterm score, and final score (all scores are of type int) 2. To read in a student’s name, use the version of read_line function that skips white-space characters before it begins storing characters. 3. The program should have a loop that continues as long as the user wants to enter another student’s record. 4. Assume that there are no more than 100 students. 5. Assume that each student’s name is no more than 50 characters long. I would like to figure out how to get the following output: The average score on quiz1 is 7.5 The average score on quiz2 is 8.5 The average score on midterm is 83.5 The average score on final is 91 The average score for the entire course is 86.375 I have been able to get the average numerical scores, but I want to be able to get the average quiz1 score, quiz2 score, midterm, final, and entire course course once I type n (for no). How could I possibly do it? #include <stdio.h> #include <ctype.h> #define NAME_LEN 50 #define STUD_LEN 100 int read_line(char str[], int n); int find_students(int students); struct test_result { char name[NAME_LEN+1]; int number; int grade1; int grade2; int midterm; int final; float numeric; }studen[STUD_LEN]; void insert(void); void print(void); int num_students = 0; int main(void) { struct test_result test; printf("Enter the student's name: "); read_line(test.name, NAME_LEN); printf("Enter the student's grade for quiz #1: "); scanf("%d", &test.grade1); printf("Enter the student's grade for quiz #2: "); scanf("%d", &test.grade2); printf("Enter the student's grade for midterm: "); scanf("%d", &test.midterm); printf("Enter the student's grade for final: "); scanf("%d", &test.final); test.numeric = (((test.grade1 + test.grade2) * 1.25) + (test.midterm * 0.25) + (test.final * 0.50)); printf("%s's numeric score for the entire course is %.1f\n", test.name, test.numeric); char code; for (;;) { printf("\n"); printf("Would you like to enter another student record? y(yes) or n(no)?"); scanf(" %c", &code); while (getchar() != '\n') /* skips to end of line */ ; switch (code) { case 'y': insert(); break; case 'n': print(); return 0; default: printf("Invalid entry. Try again.\n"); return 0; } } } int find_students(int students) { int i; for (i = 0; i < num_students; i++) if (studen[i].number == students) return i; return -1; } void insert(void) { int part_number; if (num_students == STUD_LEN) { printf("Sorry, cannot enter any more students.\n"); return; } studen[num_students].number = part_number; printf("Enter the student name: "); read_line(studen[num_students].name, NAME_LEN); printf("Enter the student's grade for quiz #1: "); scanf("%d", &studen[num_students].grade1); printf("Enter the student's grade for quiz #2: "); scanf("%d", &studen[num_students].grade2); printf("Enter the student's grade for midterm: "); scanf("%d", &studen[num_students].midterm); printf("Enter the student's grade for final: "); scanf("%d", &studen[num_students].final); studen[num_students].numeric = (((studen[num_students].grade1 + studen[num_students].grade2) * 1.25) + (studen[num_students].midterm * 0.25) + (studen[num_students].final * 0.50)); printf("%s's numeric score for the entire course is %.1f\n", studen[num_students].name, studen[num_students].numeric); num_students++; } void print(void) { printf("The average score on quiz1 is\n"); printf("The average score on quiz2 is\n"); printf("The average score on midterm is\n"); printf("The average score on the final is\n"); printf("The average score for the entire course is\n"); } int read_line(char str[], int n) { int ch, i = 0; while(isspace(ch = getchar())) ; str[i++] = ch; while ((ch = getchar()) != '\n') { if (i < n) str[i++] = ch; } str[i] = '\0'; return i; }