code output...

This is a discussion on code output... within the C Programming forums, part of the General Programming Boards category; Hi, In the program run below i get the output as follows: Enter the string Hackers have put us on ...

  1. #1
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    Question code output...

    Hi,

    In the program run below i get the output as follows:

    Enter the string
    Hackers have put us on hit list

    Hackers
    have
    put



    I had a doubt regarding the output. The program has five scanf statements and i need to pass the string "Hackers have put us on hit list" when it prompts me. Now 1st scanf and printf shoudnt the output be "ckers" instead of Hackers . But in the fourth scanf it should take "us" as the input and 's' should be the output . Similarly for the fifth scanf it takes 'on' as the input but it gives something called as '-' as output.

    insert
    Code:
    #include <stdio.h>
    #include <conio.h>
    
    void main(){
    
    	printf("Enter the string");
    
    	scanf("\n\r%s", &s[2]);
    	printf("\n\r %s", &s[2]);
    
    	scanf("\n\r%s", s);
    	printf("\n\r%s", s);
    	
    	scanf("\n%s", &s);
    	printf("\n%s", &s);
    	
    	scanf("\n%c", &s[1]);
    	printf("\n%c", &s[1]);
    	
    	scanf("\n%c", &s);
    	printf("\n%c", &s);
    }

  2. #2
    ATH0 quzah's Avatar
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    This can't possibly be the code you've tried to compile, because it doesn't.


    Quzah.
    Hope is the first step on the road to disappointment.

  3. #3
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    This is what compiles on my machine

    insert
    Code:
    #include <stdio.h>
    #include <conio.h>
    
    void main(){
    
    	static char s[30];
    	printf("Enter the string");
    
    	scanf("\n\r%s", &s[2]);
    	printf("\n\rHere %s", &s[2]);
    
    	scanf("\n\r%s", s);
    	printf("\n\r%s", s);
    	
    	scanf("\n%s", &s);
    	printf("\n%s", &s);
    	
    	scanf("\n%c", &s[1]);
    	printf("\n%c", &s[1]);
    	
    	scanf("\n%c", &s);
    	printf("\n%c", &s);
    	
    }
    Output is this:
    Enter the string
    Hackers have put us on hit list

    Here Hackers
    have
    put

    ─Press any key to continue . . .

  4. #4
    ATH0 quzah's Avatar
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    You should consider reading the FAQ on how to read lines of text.

    Cprogramming.com FAQ > Get a line of text from the user/keyboard (C)

    Also, & means 'address of', so unless you're trying to actually display the address of something, you shouldn't be using it in printf.

    Quzah.
    Hope is the first step on the road to disappointment.

  5. #5
    DESTINY BEN10's Avatar
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    @roann
    Don't use void main ever. See the FAQ.
    HOPE YOU UNDERSTAND.......

    By associating with wise people you will become wise yourself
    It's fine to celebrate success but it is more important to heed the lessons of failure
    We've got to put a lot of money into changing behavior


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  6. #6
    gcc -Wall -pedantic *.c
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    >Also, & means 'address of', so unless you're trying to actually display the address of something, you shouldn't be using it in printf

    s is an array of chars, so '&(s[N])' in a printf with the '%s' format is correct.

  7. #7
    ATH0 quzah's Avatar
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    Quote Originally Posted by flexo87 View Post
    s is an array of chars, so '&(s[N])' in a printf with the '%s' format is correct.
    Yes, but we see it first as...
    Code:
    printf("\n%s", &s);

    Quzah.
    Hope is the first step on the road to disappointment.

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