unsigned char 128

This is a discussion on unsigned char 128 within the C Programming forums, part of the General Programming Boards category; Hello, I am having troubles with char data type I am using 128 to intiallize it to my variable --> ...

  1. #1
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    unsigned char 128

    Hello,

    I am having troubles with char data type I am using 128 to intiallize it to my variable --> char x = 128; and printing it as an unsigned type (%u) I understand that when printing it as a %u it is printed as unsigned decimal integer. I have tried printf("%u",(unsigned char)x); and it does print 128 but I want to be able to print it without casting in the printf statement. Any help/feedback/thoughts would be very much appreciated.

  2. #2
    Captain Crash brewbuck's Avatar
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    If it's defined as a char, it will be passed to printf() as a char. There is no way to avoid the cast in this case. The problem is that you're trying to store 128 into a signed char, when a signed char is not capable of holding such a value.
    Code:
    //try
    //{
    	if (a) do { f( b); } while(1);
    	else   do { f(!b); } while(1);
    //}

  3. #3
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    Thanks brewbuck I knew that signed char had a range -128 to 127, was trying to see if there is workaround out there. But thank you very much for the reply.

  4. #4
    Banned ಠ_ಠ's Avatar
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    whats the point of a signed char anyway?
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  5. #5
    ATH0 quzah's Avatar
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    Quote Originally Posted by ಠ_ಠ View Post
    whats the point of a signed char anyway?
    What's the point of a signed int anyway?


    Quzah.
    Hope is the first step on the road to disappointment.

  6. #6
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    Quote Originally Posted by quzah View Post
    What's the point of a signed int anyway?


    Quzah.
    oh, they are visible characters... I didn't know that
    ╔╗╔══╦╗
    ║║║╔╗║║
    ║╚╣╚╝║╚╗
    ╚═╩══╩═╝

  7. #7
    ATH0 quzah's Avatar
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    You are aware that characters are just tiny ints, right? You aren't forced to interpret them as displayable characters. For example, this is perfectly valid:
    Code:
    char x;
    for( x = 0; x < 10; x++ )
        printf( "Yay!\n" );
    You are confusing a data type, with a character set.


    Quzah.
    Hope is the first step on the road to disappointment.

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