[Help] About reverse string

This is a discussion on [Help] About reverse string within the C Programming forums, part of the General Programming Boards category; I must Write a program using getchar() function only to read the character string from the keyboard until ‘.’ is ...

  1. #1
    Registered User
    Join Date
    May 2009
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    16

    Unhappy [Help] About reverse string

    I must Write a program using getchar() function only to read the character string from the keyboard until ‘.’ is terminated, then reverse the string and display result on on the screen.

    I don't know why but my program doesn't run right. Can anyone help me, pls. And this is my code:

    Code:
    #include<stdio.h>
    #include<conio.h>
    #include<stdlib.h>
    #include<string.h>
    
    main()
    {
       unsigned int choice, i, j, n;
       char c, temp;
       char s1[100], s2[100];
       while(1){
       do{
           system("cls");
           printf("Choose one of the following options: ");
           printf("\n1. Input a string");
           printf("\n2. Dislay a string");
           printf("\n3. Reverse a string");
           printf("\n0. Exit");
           printf("\nYour selection (0 -> 3): ");
           scanf("%d", &choice);}
       while(choice<0 || choice>3);
       switch(choice){
                         case 1: printf("\nEnter string ended by . : ");
                                 for(i=0; (c=getchar()) != '.'; i++) s1[i]=c;
                                 n=strlen(s1);
                                 for(i=0;i<n;i++)
                                    if (s1[i]=='\n') 
                                        {
                                           for(j=i;j<n;j++) s1[j]=s1[j+1];
                                           s1[n--]='\0';
                                           i--;
                                        }
                                 strcpy(s2,s1);
                                 system("pause");
                                 break;
                         case 2: printf("String entered is \" ");
                                 for(i=0;i<n;i++) printf("%c", s1[i]);
                                 printf(" \" \n");
                                 system("pause");
                                 break;
                         case 3: for(i=0;i<n-1;i++)
                                    for(j=i+1;j<n;j++)
                                    {
                                       temp=s2[i];
                                       s2[i]=s2[j];
                                       s2[j]=temp;
                                    };
                                 printf("The orginal string: ");
                                 for(i=0;i<n;i++) printf("%c", s1[i]);
                                 printf("\n");
                                 printf("The reverse string: ");
                                 for(i=0;i<n;i++) printf("%c", s2[i]);
                                 printf("\n");
                                 system("pause");
                                 break;
                         case 0: exit(0);}}
    }

  2. #2
    Registered User
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    May 2009
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    16
    I have fixed my program.
    It should have "fflush(stdin)" in case 1

  3. #3
    and the hat of wrongness Salem's Avatar
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    Erm, nope - you should have read the FAQ.
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.
    I support http://www.ukip.org/ as the first necessary step to a free Europe.

  4. #4
    Deathray Engineer MacGyver's Avatar
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    Posts
    3,211
    Congratulations on being entirley dependant on C-according-to-Borland-from-ye-olde-days-for-Windows. Bleh.

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