why the compiler skips this line..

it just skips over this

Code:

scanf("%c",&var);

instead of letting me input a char in var
??

Look in some of the half-dozen other of your threads which deal specifically with scanf issues.

And no, it's YOUR code which is the issue, not your compiler.

there is no mistake
if it was written in a wrong way
the program wouldnt have ran from the beggining

why its skipping this line
??

Originally Posted by transgalactic2

there is no mistake
if it was written in a wrong way
the program wouldnt have ran from the beggining

You code can be wrong without causing a compile error.

Originally Posted by transgalactic2

why its skipping this line
??

Because you wrote the code such that the flow of control skips that statement with the given input to your program, or maybe the flow of control does not skip that statement, but you have deceived yourself into believing that it does.

so the scanf is correct?

Originally Posted by transgalactic2

so the scanf is correct?

Maybe. Without knowing the problem, the context and what exactly is var, concluding the correctness (or lack thereof) of that call of scanf is foolish.

For example, is this correct?

Code:

foo();

maybe its skipping because of the \0 in the buffer

Okay, enough of games. Post the smallest and simplest compilable program that demonstrates the problem.

Originally Posted by transgalactic2

maybe its skipping because of the \0 in the buffer

It probably lies in the code that goes before scanf() so it's best to post the code snippet.

> there is no mistake
ROFLMAO - so says you with 1500 posts and no idea STILL how to use scanf properly.

Originally posted by brewbuck
Sit back and break out the marsh mallows.

You continue to use broken ideas, then post 1-liners with NO context, then complain that it doesn't work, and then complain at people trying to help you (futile: adj - helping transgalactic2)