Debugging bomb program

This is a discussion on Debugging bomb program within the C Programming forums, part of the General Programming Boards category; So I've been given an assignment that acts like a bomb with 6 phases to it. At each phase you ...

  1. #1
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    Debugging bomb program

    So I've been given an assignment that acts like a bomb with 6 phases to it. At each phase you are prompted to enter something that the program is looking for. If you enter correctly the program continues, if not the bomb explodes. So I've gotten the first two which were short sentences and now I'm on the third which is asking for 6 integers. My thoughts were to set the break point at the compare statement(0x080488df ) and then run the program entering 6 random integers. Then I would print eax and edx and would see the numbers I entered along with the numbers that should be entered. However my idea is incorrect as I'm not getting what I'm looking for. So if my example string is 1 2 3 4 5 6 my print statements are the following.

    print $eax = 4
    print $edx = 1

    Basically what's happening is that edx looks right but eax is not the correct number. Eax is always the fourth number I enter. For example:

    1 2 3 5 6 7

    print $eax = 5
    print $edx = 1


    So I'm lost and looking for help on how to find the first integer. I think I can take it from there. Any help is appreciated. Disassembled code below.

    0x080488a6 <phase_3+0>: push %ebp
    0x080488a7 <phase_3+1>: mov %esp,%ebp
    0x080488a9 <phase_3+3>: sub $0x28,%esp
    0x080488ac <phase_3+6>: movl $0x0,0xfffffffc(%ebp)
    0x080488b3 <phase_3+13>: lea 0xffffffe0(%ebp),%eax
    0x080488b6 <phase_3+16>: mov %eax,0x4(%esp)
    0x080488ba <phase_3+20>: mov 0x8(%ebp),%eax
    0x080488bd <phase_3+23>: mov %eax,(%esp)
    0x080488c0 <phase_3+26>: call 0x8048dac <read_six_numbers>
    0x080488c5 <phase_3+31>: movl $0x0,0xfffffff8(%ebp)
    0x080488cc <phase_3+38>: jmp 0x80488f6 <phase_3+80>
    0x080488ce <phase_3+40>: mov 0xfffffff8(%ebp),%eax
    0x080488d1 <phase_3+43>: mov 0xffffffe0(%ebp,%eax,4),%edx
    0x080488d5 <phase_3+47>: mov 0xfffffff8(%ebp),%eax
    0x080488d8 <phase_3+50>: add $0x3,%eax
    0x080488db <phase_3+53>: mov 0xffffffe0(%ebp,%eax,4),%eax
    0x080488df <phase_3+57>: cmp %eax,%edx
    0x080488e1 <phase_3+59>: je 0x80488e8 <phase_3+66>
    0x080488e3 <phase_3+61>: call 0x804906c <explode_bomb>
    0x080488e8 <phase_3+66>: mov 0xfffffff8(%ebp),%eax
    0x080488eb <phase_3+69>: mov 0xffffffe0(%ebp,%eax,4),%eax
    0x080488ef <phase_3+73>: add %eax,0xfffffffc(%ebp)
    0x080488f2 <phase_3+76>: addl $0x1,0xfffffff8(%ebp)
    0x080488f6 <phase_3+80>: cmpl $0x2,0xfffffff8(%ebp)
    0x080488fa <phase_3+84>: jle 0x80488ce <phase_3+40>
    0x080488fc <phase_3+86>: cmpl $0x0,0xfffffffc(%ebp)
    0x08048900 <phase_3+90>: jne 0x8048907 <phase_3+97>
    0x08048902 <phase_3+92>: call 0x804906c <explode_bomb>
    0x08048907 <phase_3+97>: leave
    0x08048908 <phase_3+98>: ret
    Last edited by Mike_Smith; 05-25-2009 at 03:45 PM.

  2. #2
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    nvm...got it

  3. #3
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    how did you solve phase_
    3, please give me some hints i am really stuck on finding the first integer in phase_3

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    Bumping a thread over a year old - see the rules.
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