Quick help needed on simple example

Code:

char c=0;
int letter [3];

letter[0]=0; letter[1]=0; letter[2]=0;

printf("please enter a letter");
scanf("%c", &c);

switch (c) {
case 'a': letter[0]++;
case 'b': letter[1]++;
default: letter[2]++;
}
printf("%d %d %d", letter[0], letter[1], letter[2]);

Can someone please explain what line2 is actually doing. Is it there to define how many "letter" variations there are (i.e letter[0]...), or does it do something else?

Also because letter[0]=0 for example isnt given a value type, but it follows on from an int being defined, is it reasonable to assume letter[0] is being defined as an int as well?

Hello.

Line 2 says: "letter is an array of 3 integers.". There is nothing more to it.

Is this even being used in the code though. I can see letter[0], letter[1] and letter[2], but no mention of just letter.

Sorry if im being dumb.

letter[0] is the first element of the array declared on line 2. letter[1] is the second element of the array, etc.

--
Mats

Ah i understand now, thank you.

Originally Posted by hiven

Code:

char c=0;
int letter [3];

letter[0]=0; letter[1]=0; letter[2]=0;

printf("please enter a letter");
scanf("%c", &c);

switch (c) {
case 'a': letter[0]++;
case 'b': letter[1]++;
default: letter[2]++;
}
printf("%d %d %d", letter[0], letter[1], letter[2]);

Can someone please explain what line2 is actually doing. Is it there to define how many "letter" variations there are (i.e letter[0]...), or does it do something else?

Also because letter[0]=0 for example isnt given a value type, but it follows on from an int being defined, is it reasonable to assume letter[0] is being defined as an int as well?

Your code is really ate up. I'm not really sure what your trying to acheive.

Code:

#include <stdio.h>

int main(void)
{
   char c;
   int letter [3] = {0};


   printf("please enter \"a\" or \"b\": ");
   scanf("%c", &c);

   switch (c) 
   {
      case 'a': 
         ++letter[0];
         break;
      case 'b': 
         ++letter[1];
         break;
      default: 
         ++letter[2];
   }
   printf("\nletter[0] contains: %d\nletter[1] contains:"
            " %d\nletter[2] contains: %d", letter[0], letter[1], letter[2]);
   
   fflush(stdin);
   getchar();
   return 0;
}

You really need a break in those cases or else all the cases will be performed.
edit: unless its your intention to add one to letter[1] and letter[2] when you enter a to add
one to letter[0]

do not fflush stdin - read FAQ