Easy String position question...

Been out of the programming loop for awhile, and trying to ease myself back in. My first self appointed project has me stumped so thought I'd fire off a quick easy question for all the pros here on the board.

I have a string that i have a variable in, its 26 characters long. I want to read say the 10th character in. Is there a relatively easy way to find that? Here's what i have so far:

Code:

#include <stdio.h>

int main()
{
        char test[] = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
        char single_test[] = " ";

        clrscr();

        /* Print test characters */
        printf("Variable: %s\r\n", test);

        /* Code here to go 10 characters out, and set the variable */
 
   /*  for ( i = 0; i < 10; ++i ) {
        single_test = strsomething  

        } */
    
        /* Print 10th character */
        printf("The 10th character is: %s\r\n", single_test);

        getch();

}

Any help would be appreciated.

If you want a single character, you want to use %c. You can use a character pointer, and increment it. Or you can use array[ x ] to find the spot. Remember that array indexes start at zero, not 1.


Quzah.

Just enough to jumpstart my brain. Thanks! Basically i have a 24x80 map that a person can move around. I wanted to be able to find their position on the screen, and if that position was equal to a T, then do something. I think this below will work out.

Code:

#include <stdio.h>

int main()
{
        char test[] = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
        char single_test[] = " ";
        int i;

        clrscr();

        printf("Variable: %s\r\n", test);

        /* Code here to go 10 characters out, and set the variable */

        for (i = 0; i < 26; i++) {
        if (test[i] == 'T')
        printf("The %dth character is: %c\r\n", i + 1, test[i]); }

        getch();

}

Works great in this setup, just need to plug it into my movement routine.

example for find character in array and print its index (somewhere I was write it here already)

Спасибо