Meaning of the instruction >>=

**frodo_jedi** · 05-07-2009

Hello,
I do not know what this instruction does:
temp >>= 15;

The context where I found is:

Code:

int my_random(int max)  {   //  Return Random Int Between 0 and max
	unsigned long temp;
  	temp = (unsigned long) rand();
	temp *= (unsigned long) max;
	temp >>= 15;
	return (int) temp; 
}

Help!

**matsp** · 05-07-2009

It is, technically, not an instruction, but an operator. What does a += 4 do? Do you know what >> does? If you know both of those, it should be obvious...

--
Mats

**stevesmithx** · 05-07-2009

">>=" is a bitwise assignment operator.

Code:

temp >>= 15;

means right shift temp by 15 and assign it back to temp.

**shwetha_siddu** · 05-07-2009

Originally Posted by stevesmithx

">>=" is a bitwise assignment operator.

Code:

temp >>= 15;

means right shift temp by 15 and assign it back to temp.

Go throgh following code

Code:

int main(int argc, char* argv[])
{
  int tmp = 0xffff;
  printf("%d", tmp = tmp >> 15);  //tmp >>= 15 same as tmp = tmp >> 15
   return 0;

}

Ouput is 1

**BEN10** · 05-07-2009

Originally Posted by frodo_jedi

Hello,
I do not know what this instruction does:
temp >>= 15;

The context where I found is:

Code:

int my_random(int max)  {   //  Return Random Int Between 0 and max
	unsigned long temp;
  	temp = (unsigned long) rand();
	temp *= (unsigned long) max;
	temp >>= 15;
	return (int) temp; 
}

Help!

x=a>>n
x will be equal to a divided by 2 raised to the power n.

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Meaning of the instruction >>=

Right shift by 15 times contents of tmp

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