Guess the number program help needed

Hello

first part of assignment I completed which was to create a guess the number prog. 2nd part I have to limit # of tries.. less than 10 print either u know r u got lucky , =10 print ahah u know the secret, or lmore than 10 u should be able to do better.. i been trying to plug in if tries=10, <10 , >10 etc but that doesn't work..not sure where i would place it. can someone assist.

thanks!

Code:

---

#include<stdio.h>
#include<time.h>
#include<stdlib.h>

int main(void)
{
        int theNumber;
        int tries,guess,yesno=1;
        srand (time(0));
        do
        {
                theNumber=rand()% 1000+1;
                tries=0;
                printf("I have a number between 1 and 1000.""Can you guess my number? \n\n");
                do
                {
                        printf("Please type your first guess:");
                        scanf("%d",&guess);
                        ++tries;
                        if (guess > theNumber)
                                printf("To high!! Try again.\n\n");
                        if (guess < theNumber)
                                printf("To low!! Try again. \n\n");                       
                }
                while (guess != theNumber);
                printf("Excellent! You guessed the number!\n");
                printf("Would you like to play again?\n");
                printf("Please type (1=yes, 2=no)?\n");
                scanf("%d",&yesno);
        }
        while(yesno==1);
        return 0;
}

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The tries part goes inside the nested do-while loop (the one where you keep guessing).

printf("I have a number between 1 and 1000.""Can you guess my number? \n\n");

should be

printf("I have a number between 1 and 1000. Can you guess my number? \n\n");

Only error I can see.

To test the guesses against the number, your best bet is just to use if, else if and else statements.

Quote:

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Originally Posted by DeadPlanet

printf("I have a number between 1 and 1000.""Can you guess my number? \n\n");

should be

printf("I have a number between 1 and 1000. Can you guess my number? \n\n");

Only error I can see.

---

That is not an error since adjacent string literals are automatically concatenated.

Quote:

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Originally Posted by msbrownsugah

Hello

first part of assignment I completed which was to create a guess the number prog. 2nd part I have to limit # of tries.. less than 10 print either u know r u got lucky , =10 print ahah u know the secret, or lmore than 10 u should be able to do better.. i been trying to plug in if tries=10, <10 , >10 etc but that doesn't work..not sure where i would place it. can someone assist.

thanks!

---

I've modified the code. It should work.(sorry for the indentation part)

Code:

---

#include<stdio.h>
#include<time.h>
#include<stdlib.h>

int main(void)
{
        int theNumber;
        int tries,guess,yesno=1;
        srand (time(0));
        do
        {
                theNumber=rand()% 1000+1;
                tries=0;
                printf("I have a number between 1 and 1000.""Can you guess my number? \n\n");
                do
                {
                        printf("Please type your first guess:");
                        scanf("%d",&guess);
                        ++tries;
                        if (guess > theNumber)
                                printf("To high!! Try again.\n\n");
                        if (guess < theNumber)
                                printf("To low!! Try again. \n\n");                       
                }
                while (guess != theNumber && tries<=10);
                                if(tries<10)
                printf("either u know or u got lucky ");
                                else if(tries==10)
                                printf("ahah u know the secret");
                              else
                                printf(" u should be able to do better");
                printf("Would you like to play again?\n");
                printf("Please type (1=yes, 2=no)?\n");
                scanf("%d",&yesno);
        }
        while(yesno==1);
        return 0;
}

---

Quote:

---

Originally Posted by laserlight

That is not an error since adjacent string literals are automatically concatenated.

---

Wow, it's funny that on the only day I've even seen something like that, is the day that I read about it 3 hours after I've just told someone it was wrong. :D

Sorry about that ;)

Quote:

---

Originally Posted by DeadPlanet

Wow, it's funny that on the only day I've even seen something like that, is the day that I read about it 3 hours after I've just told someone it was wrong. :D

Sorry about that ;)

---

Sorry to side-track, but it comes in REAL handy when you have things like menus and such to print:

Code:

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printf("1. Add...\n"
      "2. Delete...\n"
      "3. List...\n"
      "0. Exit...\n");

---

is much easier to read/follow than a single line with embedded newlines, without adding extra calls to printf.

--
Mats

ok thanks for that help i got some errors but i was able to figure it out.

lastly i am so confuse on this part and it may be so simple... i have to include in the program a function which displays a header with my name and brief description of the program. than Write the portion of the program that gathers new guesses as a separate function and Write the portion of the program that checks the new guesses as a separate function also Define all the function prototypes in a header file and include the function definitions as a
separate C file.

im like huh???!