help getting a grib on argc and argv

This is a discussion on help getting a grib on argc and argv within the C Programming forums, part of the General Programming Boards category; hello people i m srry i kinda dont understand the need of argc and argv like i dunno what they ...

  1. #1
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    help getting a grib on argc and argv

    hello people i m srry i kinda dont understand the need of argc and argv like i dunno what they do like for example this code here it doesnt even run or anything
    Code:
    #include < stdio.h>
    int main(int argc, char** argv)
    {
        int i;
        printf("argc = %d\n", argc);
        for (i = 0; i < argc; i++)
    	    printf("argv[%d] = \"%s\"\n", i, argv[i]);
    	return 0;
    }
    it would be be cool if someone like give me the idea on how they work

  2. #2
    C++ Witch laserlight's Avatar
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    To get a grip on command line arguments read the tutorial.
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    oh i understand it now but will it only work in cmd ? like can i also use command line arguments to like produce a programmer that opens a txt ? without cmd like in a window ? or argc and argv used only with cmd ?

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    Please post clear questions? From your last post it is impossible to figure out what you're tryin' to say.

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    like i got a txt file on the same folder i m in is it possible to make a program that opens it without needing to add do it from cmd like from the program itself?

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    like when you like have a text file like in the same like folder u like just add its path to like the cmd line of the program in like cmd like so you like can get like the filename from like argv and u like not have to like hardcode it like in the source code itself like that

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    like ROTFLOL

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    Quote Originally Posted by MWAAAHAAA View Post
    like when you like have a text file like in the same like folder u like just add its path to like the cmd line of the program in like cmd like so you like can get like the filename from like argv and u like not have to like hardcode it like in the source code itself like that
    english isnt my main language so if it makes you feel better to make fun of my talking then go ahead

  9. #9
    Captain Crash brewbuck's Avatar
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    Quote Originally Posted by elwad View Post
    english isnt my main language so if it makes you feel better to make fun of my talking then go ahead
    There's no need to butcher simple works like "sorry."

    And your language is so idiosyncratic I have a hard time believing you're not a native English speaker, but like, whatever and stuff.

    (Idiosyncratic doesn't mean "idiotic")
    Code:
    //try
    //{
    	if (a) do { f( b); } while(1);
    	else   do { f(!b); } while(1);
    //}

  10. #10
    Frequently Quite Prolix dwks's Avatar
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    To answer a question that the OP may have been asking: it is possible to associate your program with .txt files (either by clicking on it normally or having a separate item in the right-click menu) so that when you choose to open a file with your program, the full path to the file you opened is passed as a command-line parameter to your program. I'm not going to say more than that in case I'm on the wrong track here . . . .
    dwk

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    here is a sample assigment i did from the k&r book which uses the commandline arguments . i think some gui libraries uses commandline parameters internally to keep track of some things but i am not that far into my studies of c that i can say if that is true or not.
    Code:
    #include <stdio.h>
    #define IN 1
    #define OUT 0
    
    int main(int argc,char *argv[]){
    	
    	int c;
    	int nl,nw,nc,state;
    	    nl=nw=nc=state=0;
    	FILE *fp;
    	
    	if(argc != 2)
    	  {
    	  	fprintf(stderr," %s: too few arguments for format\n",argv[0]);
    	  	return 1;
    	  }
    	  
    	  if((fp=fopen(argv[1],"r")) != NULL)
    	  {
    		/* we opened a file to read it and count it*/
            while((c=getc(fp))!= EOF)
    	 {
    	     	   nc++;
    	     	if(c=='\n')
    	     	  nl++;
    	        if(c==' '||c=='\n'||c=='\t')
    	           state=OUT;
    	          else if(state == OUT)
    	          {
    	          	state = IN;
    	          	++nw;
    		  }
    	}
    		fprintf(stdout,"%d %d %d\n",nl,nw,nc);
    	}
            else
            {
    		fprintf(stderr,"error in opening file %s\n",argv[1]);
    		return 1;
    	}
    		return 0;
    }
    i am not sure if you can read it and i waiting for a eye operation so i read and write really bad at the moment but i hope it was helpful -(and i posted it in t he right context if not then ignore post please. )

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