Need help with problem set

This is a discussion on Need help with problem set within the C Programming forums, part of the General Programming Boards category; Ok, so my beginning to C programming class has started and I have understood the concepts thus far. There is ...

  1. #1
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    Need help with problem set

    Ok, so my beginning to C programming class has started and I have understood the concepts thus far. There is this one programming excercise I am having an issue with. The excercise asks you to create a program that results in the following output:

    Smile!Smile!Smile
    Smile!Smile!
    Smile!

    The only requirement is that I use a function that prints smile once, and then calling upon that function as many times as required to produce the above output. The following is what I have s o far

    #include <stdio.h>
    int main (void)
    {
    smile(), smile(), smile();
    smile(), smile();
    smile();
    return 0;
    }
    void smile (void)
    {
    printf("Smile!");
    }

    This is producing an output of

    Smile!Smile!Smile!Smile!Smile!Smile!

    I know I need a line break ("\n") some where in there, but where. I have tried putting it everywhere and cannot seem to get the require output.

    BTW im using Ubuntu Intrepid Ibex server with GCC . My prog is compiling without error, I know I am missing something.

    Your help is greatly appreciated!

  2. #2
    ATH0 quzah's Avatar
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    You should consider using a loop, and a counter, which decreases and keeps track of how many time to call your function before it writes a newline.


    Quzah.
    Hope is the first step on the road to disappointment.

  3. #3
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    between the calls to smile();

    Also,
    Code:
    smile(), smile(), smile();
    is more conventionally written
    Code:
    smile(); smile(); smile();

  4. #4
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    Code:
    #include <stdio.h>
    
    void smile(void);   // Function prototype ; required if you put your functions 
                                 //after main
    
    int main (void)
    {
       int count1;
       int count2;
       
       for(count1 = 3; count1 > 0; --count1)
      {
          for(count2 = count1; count2 > 0; --count2) 
          {   
           smile();
           }
       printf("\n");
       }
    return 0;
    }
    void smile (void)
    {
    printf("Smile!");
    }
    Last edited by strictlyC; 04-17-2009 at 10:24 PM.

  5. #5
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    What about if you had a for loop in main(). It could call smile() every time through the loop, and you could set it up to count backward: 3,2,1


    In main()

    Code:
    for( i = 3; i > 0; i--)
       smile(i);
    In smile:

    Code:
    void smile(int j)  {
    
    for( ; j > 0; j--)
       printf("smile");
    
    print your newline, here.
    
    }
    So the effect is the same as a double for loop to do this, in main(), but it shows how you want to break apart problems, into smaller sub-problems, and split them up among different smaller functions.

    Do you see how the variable i, is turned into j inside smile() ? That's why there's no assignment in smile's for loop, for j. It's already got the right value.

  6. #6
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    Please don't do people's homework for them. They learn more figuring it out themselves.

  7. #7
    ATH0 quzah's Avatar
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    God damn you people irritate me. There's a reason I didn't just do the loop for him.


    Quzah.
    Hope is the first step on the road to disappointment.

  8. #8
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    Code:
    #include <stdio.h>
    
    void smile(int i);
    
    int main (void)
    {
       smile(6);
    }
    
    
    void smile (int i)
    { 
       if(i == 1 || i == 3)
          printf("\n");
       
       if(i){
          printf("Smile!");
          smile(--i);
       }
    }

    Just for fun... and apparrently to irritate quzah
    Edited a little now I'm happy.
    Last edited by strictlyC; 04-17-2009 at 10:15 PM.

  9. #9
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    Code:
    #include <stdio.h>
    
    void smile (void)
    { 
       printf("Smile!");
    }
    
    int main (void)
    {
       for(int i = 6; i != 0; --i)
       {
          if(i == 1 || i == 3)
             printf("\n");
          smile();
       }
    }
    Much better than the first one I posted...

  10. #10
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    I appreciate all of the ideas, but I think you are all complicating the problem. We were instructed not to use anything that the class hasnt covered yet which would include loops and counters. There has to be a simpler way of doing this. Thanks for all of your responses, I will take it from here. I dont want to upset anyone with my homework.

  11. #11
    C++ Witch laserlight's Avatar
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    Quote Originally Posted by On51aught
    We were instructed not to use anything that the class hasnt covered yet which would include loops and counters. There has to be a simpler way of doing this.
    In that case you should break up your function calls. First, call smile() three times, then call printf() (or puts()) to print a newline. Then call smile() twice, etc.
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  12. #12
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    Thats exactly what I just finished doing. I guess I was also making this problem harder than it really was. I just used a printf function to print a new line. The following is what I got

    Code:
    #include <stdio.h>
    void smile (void);
    int main (void)
    {
    smile();smile();smile();printf("\n");
    smile();smile();printf("\n");
    smile();printf("\n");
    return 0;
    }
    void smile (void)
    {
    printf("Smile!");
    }
    Again thanks for the help, I am not looking for people to do my homework for me by any stretch, just some boots in the rear towards the right direction. Thanks again to all that responded. I might play with the loop and counter idea just to see if I can get it to work.

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