Just check this if I am right please.

Code:

---

#include <stdio.h>
#include <conio.h>
struct emp
{
        char name[25];
  int age;
  int salary;
};
void fn1(char*,int,int);
void main()
{
        struct emp emp_1[3];
  int i;
  for(i=0;i<3;i++)
  {
                printf("Enter name age and salary of number %d\n",i);
          scanf("%s%d%d",&emp_1[i].name,&emp_1[i].age,&emp_1[i].salary);
  }
  for(i=0;i<3;i++)
  {
      fn1(emp_1[i].name,emp_1[i].age,emp_1[i].salary);
  }
  getch();
}
void fn1(char *ch,int a,int b)
{
        printf("\n\nName is %s\nAge is %d\nSalary is %d\n",ch,a,b);
}

---

That above is my answer to the qtn.
WAP to accept values in structure array and pass it to a function to print the values
Is there any way that I can pass the whole structure to fn1 without putting it in a for loop?

Code:

---

for(i=0;i<3;i++)
  {
      fn1(emp_1[i].name,emp_1[i].age,emp_1[i].salary);
  }

---

just straightaway like

Code:

---

void fn1(struct emp empl_1)

---

or something like that?

Thanks in advance

Yes, you can pass a structure to a function.

--
Mats

Quote:

---

Originally Posted by matsp

Yes, you can pass a structure to a function.

--
Mats

---

And how may I do that?

Quote:

---

Originally Posted by aditya_t90

And how may I do that?

---

Using a pointer:

Code:

---


#include <stdio.h>

struct eg {
        char *data;
};

void test (struct eg *here) {
        printf("voila: %s\n",here->data);
}

int main () {
        char this[]="message";
        struct eg look;
        look.data=this;
        test(&look);
        return 0;
}

---

* for pointer
-> for pointer property (indirect notation)
& address of operator (so a pointer to the address)

just a general tip. I would avoid using variable named this. It may be confusing, especially for programmers using mainly c++. Ive personally used _this, when i've had a struct whìch has been used like a class in cpp. I can also imagine that variable named this might cause problems in interface functions declaration, which may be used with cpp. Although extern "C" might help compiler to handle that correctly.

Quote:

---

Originally Posted by Maz

just a general tip. I would avoid using variable named this. It may be confusing, especially for programmers using mainly c++. Ive personally used _this, when i've had a struct whìch has been used like a class in cpp. I can also imagine that variable named this might cause problems in interface functions declaration, which may be used with cpp. Although extern "C" might help compiler to handle that correctly.

---

Yes "this" is a keyword in some languages like ecmascript+html
I removed the word "this" with something else.
I seem to have finally got the program right.
Anyone will check if this conforms to standards

Code:

---

#include <stdio.h>
#include <conio.h>

struct emp
{
  char name[25];
  int age;
  int salary;
};

void fn1(struct emp *);

void main()
{
  struct emp emp_1[3];
  int i;     
  for(i=0;i<3;i++)
  {
          printf("Enter name age and salary of number %d\n",i);
          scanf("%s%d%d",&emp_1[i].name,&emp_1[i].age,&emp_1[i].salary);
  }
  fn1(emp_1);
  getch();
}

void fn1(struct emp *here)
  {
        int y;
        for(y=0;y<3;y++)
  {
                printf("\n\nName is %s\nAge is %d\nSalary is %d\n",here[y].name,here[y].age,here[y].salary);
  }
}

---

The code might not be indented properly here coz, I just copy pasted it from borland c++
The above program takes a struct array of employee names ages and salaries and passes it to a function which prints it.
It works just as indented in borland c++

Thanks for all the help

i am browsing the site with mobile, and it is a bit painfull to browse the code... But quick check reveals a few problems regarding standards. Void main and getch

also here

Code:

---

scanf("%s%d%d",&emp_1[i].name,&emp_1[i].age,&emp_1[i].salary);

---

red ampersand to be removed

as a side not function prototype could be make to accept const pointer as it does not modify the struct:

Code:

---

void fn1(const struct emp * pArr);

---

Thanks everyone.
Vart could you please elaborate on...

Quote:

---

Originally Posted by vart

also here
as a side not function prototype could be make to accept const pointer as it does not modify the struct:

Code:

---

void fn1(const struct emp * pArr);

---

---

what is pArr?
is is a variable name or something or is is a keyword?

Thanks

It is a parameter name, though in the context of a function prototype the parameter name is not significant.

Quote:

---

Originally Posted by aditya_t90

Thanks everyone.
Vart could you please elaborate on...



what is pArr?
is is a variable name or something or is is a keyword?

Thanks

---

yes it is argument name - better practice is not to leave it out even in the function declaration...

naming it pArr or some other variant like empArray etc - I just hint the reader of the code that function expects an array of structs and not just one struct...

of course mode descriptive prototype would look like

Code:

---

void fn1(const struct emp * pArr, size_t arrSize);

---

so your function should not guess the correct array size and thus could not read beyond the array bounds when the array size in the calling function will be changed by someone

PS. on the other hand the prototype

Code:

---

void fn2(const struct emp * pCurrentEmployee);

---

hints the reader that the function works with only one struct instance