Coding noob - Hello World?

This is a discussion on Coding noob - Hello World? within the C Programming forums, part of the General Programming Boards category; Im so super noobie at programming - Code: #include "stdafx.h" int _tmain(int argc, _TCHAR* argv[]) { const char text = ...

  1. #1
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    Coding noob - Hello World?

    Im so super noobie at programming -

    Code:
    #include "stdafx.h"
    
    
    int _tmain(int argc, _TCHAR* argv[])
    
    {
    	const char text = Hello World;
    	char text[15];
    	printf("%c", text);
    	return 0;
    }
    What im trying to do in the simple bit of code is define a vairable at the top, in this case, I want the variable text to be "Hello". I then want to print this variable below.

    What am i doing wrong?

  2. #2
    CSharpener vart's Avatar
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    Code:
    int main(void)
    {
       const char* text = "Hello world";
       printf("%s\n",text);
       return 0;
    }
    look at the red parts
    The first 90% of a project takes 90% of the time,
    the last 10% takes the other 90% of the time.

  3. #3
    spurious conceit MK27's Avatar
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    Quote Originally Posted by spadez View Post
    What am i doing wrong?
    A bunch of things. You need to include stdio.h for printf:
    Code:
    #include <stdio.h>
    You must quote string literals:
    Code:
    "Hello World"
    You try to assign a string to a single char:
    Code:
    const char text =
    then you redefine "text" as something else
    Code:
    char text[15];
    And your printf template should contain %s, not %c.
    C programming resources:
    GNU C Function and Macro Index -- glibc reference manual
    The C Book -- nice online learner guide
    Current ISO draft standard
    CCAN -- new CPAN like open source library repository
    3 (different) GNU debugger tutorials: #1 -- #2 -- #3
    cpwiki -- our wiki on sourceforge

  4. #4
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    Code:
    #include <stdio.h>
    #include "stdafx.h"
    
    
    int _tmain(int argc, _TCHAR* argv[])
    
    {
    	const char* text ="Hello World";
    	printf("%s", text);
    	return 0;
    }
    Thank you for the help. Can you explain what the * is for next to char? This is my code above. It compiles and works, is it now properly coded?

    Edit: Since there are no arguments - can i change int main to (void) instead of (int argc, _TCHAR* argv[])

  5. #5
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    It means it's a pointer
    Cprogramming.com Tutorial: Pointers

  6. #6
    CSharpener vart's Avatar
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    Quote Originally Posted by spadez View Post
    Can you explain what the * is for next to char? This is my code above.
    char in C could store only 1 character, to build a string you need an array of characters
    "Hello world" is string literal - it means array of characters stored somewhere by the compiler, and you have only read access to it. Your text variable is a pointer to this string.
    you can look at the tutorial section on this site - it has a lesson about strings as well
    C Strings - C++ Tutorial - Cprogramming.com

    Edit: Since there are no arguments - can i change int main to (void) instead of (int argc, _TCHAR* argv[])
    yes - read FAQ CProgramming.com FAQ > main() / void main() / int main() / int main(void) / int main(int argc, char *argv[])
    The first 90% of a project takes 90% of the time,
    the last 10% takes the other 90% of the time.

  7. #7
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    Thank you for the links, ive printed them off and im going to read though them now.

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