Coding noob - Hello World?

Im so super noobie at programming -

Code:

---

#include "stdafx.h"


int _tmain(int argc, _TCHAR* argv[])

{
        const char text = Hello World;
        char text[15];
        printf("%c", text);
        return 0;
}

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What im trying to do in the simple bit of code is define a vairable at the top, in this case, I want the variable text to be "Hello". I then want to print this variable below.

What am i doing wrong?

Code:

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int main(void)
{
  const char* text = "Hello world";
  printf("%s\n",text);
  return 0;
}

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look at the red parts

Quote:

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Originally Posted by spadez

What am i doing wrong?

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A bunch of things. You need to include stdio.h for printf:

Code:

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#include <stdio.h>

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You must quote string literals:

Code:

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"Hello World"

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You try to assign a string to a single char:

Code:

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const char text =

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then you redefine "text" as something else

Code:

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char text[15];

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And your printf template should contain %s, not %c.

Code:

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#include <stdio.h>
#include "stdafx.h"


int _tmain(int argc, _TCHAR* argv[])

{
        const char* text ="Hello World";
        printf("%s", text);
        return 0;
}

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Thank you for the help. Can you explain what the * is for next to char? This is my code above. It compiles and works, is it now properly coded?

Edit: Since there are no arguments - can i change int main to (void) instead of (int argc, _TCHAR* argv[])

It means it's a pointer
Cprogramming.com Tutorial: Pointers

Quote:

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Originally Posted by spadez

Can you explain what the * is for next to char? This is my code above.

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char in C could store only 1 character, to build a string you need an array of characters
"Hello world" is string literal - it means array of characters stored somewhere by the compiler, and you have only read access to it. Your text variable is a pointer to this string.
you can look at the tutorial section on this site - it has a lesson about strings as well
C Strings - C++ Tutorial - Cprogramming.com

Quote:

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Edit: Since there are no arguments - can i change int main to (void) instead of (int argc, _TCHAR* argv[])

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yes - read FAQ CProgramming.com FAQ > main() / void main() / int main() / int main(void) / int main(int argc, char *argv[])

Thank you for the links, ive printed them off and im going to read though them now.