Hi,
I have written a function which read some bytes then convert it to int type
and I want it still keep the negative number, ex: 0xFFFF = -1
my sample code:
That is read 3 bytes, If it read 0xFFFFFF, the value is 16777215.Code:FILE * fp; int value = 0; int read_num = 3; .... fread(&value, read_num, 1, fp);
But I want get the negative number -1.
And, If read 2 (or 4 bytes), the 0xFFFF (or 0xFFFFFFFF) also need to convert to -1.
Thank you!!
so check the value of 16th bit (when you read 2 bytes) or 24th bit whenyou read 3 bytes
if this bit is 1 - fill the "unread bytes" with 0xFF if thats what you want
if you just want replace 0xFFFF with -1
is simplest wayCode:if(number == 0xFFFF) number = -1;
All problems in computer science can be solved by another level of indirection,
except for the problem of too many layers of indirection.
– David J. Wheeler
Sorry I did not explain clear enough
If the first bit is 1 (0x8000~0xFFFF)
the value should be a negative number (-32768 ~ -1)
If the first bit is 0 (0x0000~0x7FFF)
the value should be a positive number (0 ~ 32767)
Thank you!!
why not to read into short int and then assign to int?Originally Posted by umm
All problems in computer science can be solved by another level of indirection,
except for the problem of too many layers of indirection.
– David J. Wheeler
Because I need read 1~4 Bytes in different case.
Thank you
Then try to implement the algorithm I have suggested earlier
All problems in computer science can be solved by another level of indirection,
except for the problem of too many layers of indirection.
– David J. Wheeler
Thank you so much!!
Basically vart's method:
Works for read_num being 1, 2, 3, or 4 bytes... or even higher if whatever data type is value might be 64-bit integer. Algorithm sizes to fit.Code:if (((char *)&value)[read_num - 1] & 128) for (i = read_num; i < sizeof(value); i++) ((char *)&value)[i] = 255;
