Thread: is this the same thing.

I think so - but if you find code that does this sort of thing (or similar things), stay away!

--
Mats

Why don't you write a simple program to check just that?

Code:

if ((&(A[5]))-3) == (A+2)) {
  printf ("same addr!\n");
} else {
  printf ("doh!\n");
}

(Just for the record: Yes they will point to the same addr)

Edit: I are the slowpoke!

Originally Posted by transgalactic2

when i say

*((&(A[5]))-3).value=7;

it the same as saying
*(A+2).value=7
??

Which can be simplified furthur to just:

Code:

A[2].value = 7;

Also, true you can't do &t = ...
but you already know you can do t = ...
AND you know that *&t is the same as t
therefore *&t = ... is fine.
It is also perfectly fine to go

Code:

if (&t == ...)

because that doesn't involve assignment.