String Conversion

This is a discussion on String Conversion within the C Programming forums, part of the General Programming Boards category; i have the char value that contain the hexadecimal input. char Val2[9]; strncpy (Val2, buffer+8, 8); Val2[8]="

Thread: String Conversion

"; printf("\nValue 2 : ...

  1. #1
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    String Conversion

    i have the char value that contain the hexadecimal input.

    char Val2[9];
    strncpy (Val2, buffer+8, 8);
    Val2[8]="\0";
    printf("\nValue 2 : %s", Val2);

    the Val2 value need to assign to :

    int ptext[0].

    how can i do that?

    thanks

  2. #2
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    Some questions?
    • What will Val2 contain after your call to strncpy(..)?
    • Will this always be a valid hexadecimal number represented as a string? (i.e. "0x0A", "0xDEADBEEF", etc)


    Without knowing exactly what you have in mind, I think that the function int sscanf(const char *str, const char *format, ...); might solve your issues.

    a simple example:
    Code:
    #include <stdlib.h>
    #include <stdio.h>
    
    int
    main (int argc, char **argv)
    {
      char *str = "0x4a";
      int n;
    
      sscanf (str, "%x", (unsigned int *) &n);
      printf ("n = %d\n", n);
    
      return 0;
    }
    Last edited by edoceo; 03-17-2009 at 09:30 AM. Reason: typo

  3. #3
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    Quote Originally Posted by 6kyAngel View Post
    i have the char value that contain the hexadecimal input.

    char Val2[9];
    strncpy (Val2, buffer+8, 8);
    Val2[8]="\0";
    printf("\nValue 2 : %s", Val2);

    the Val2 value need to assign to :

    int ptext[0].

    how can i do that?

    thanks
    can you explain can we declare val2[9] variable name like this?
    And tell me what this program do?
    Last edited by CornedBee; 03-17-2009 at 08:15 AM.

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