i have the char value that contain the hexadecimal input.

char Val2[9];
strncpy (Val2, buffer+8, 8);
Val2[8]="\0";
printf("\nValue 2 : %s", Val2);

the Val2 value need to assign to :

int ptext[0].

how can i do that?

thanks

Some questions?

• What will Val2 contain after your call to strncpy(..)?
• Will this always be a valid hexadecimal number represented as a string? (i.e. "0x0A", "0xDEADBEEF", etc)

Without knowing exactly what you have in mind, I think that the function int sscanf(const char *str, const char *format, ...); might solve your issues.

a simple example:

Code:

#include <stdlib.h>
#include <stdio.h>

int
main (int argc, char **argv)
{
  char *str = "0x4a";
  int n;

  sscanf (str, "%x", (unsigned int *) &n);
  printf ("n = %d\n", n);

  return 0;
}

Originally Posted by 6kyAngel

i have the char value that contain the hexadecimal input.

char Val2[9];
strncpy (Val2, buffer+8, 8);
Val2[8]="\0";
printf("\nValue 2 : %s", Val2);

the Val2 value need to assign to :

int ptext[0].

how can i do that?

thanks

can you explain can we declare val2[9] variable name like this?
And tell me what this program do?