Thread: Here's another prgram I need help on!

Write a program that finds the smallest of several integers. Assume that the first value read specifies the number of values remaining.


I have most of it but im missing some stuff. I know its a loop.

Code:

#include <stdio.h>

int main () {

	int integer;
	int min;
	int counter;

	prinf("Enter integer");
	scanf("%d", &integer);


	
	min = 9999;
	integer = 0;
	
	if(integer < min){ 
		min = integer;

}

	printf("The smallest integer is %d", min);

	return 0;
}

I suggest setting min to the first integer to be compared instead of 9999, that way it will work if your smallest value is > 9999

Originally Posted by Adak

If you see the program skipping over the scanf() calls, remove the slashes before the getchar() lines of code.

I think you meant

Code:

for(i=0; i < counter; i++)

not

Code:

for(i=0; i < num; i++)

Reply to his updated code in the other thread:

Code:

	counter = 0;
	min = ;
	counter++;

what? why not just define counter = 1

Code:

if(integer > counter){ 
		min = min;

what?

Code:

else(integer == counter);

you don't use argument lists after an else statement, you would need an else if statement