In the following program, why is integer variable i also available to prlt(int i)?
Code:main() /* The main() function definition */ { int i=5; /* Define an integer variable */ prIt(i); /* Calls the prIt() function and passes it i */ return 0; /* Return to the operating system */ } prIt(int i) /* The prIt() function definition */ { printf("%d \n", i); /* Calls the printf() function */ return 0; /* Returns to main() */ }
Notice that the prIt function has a parameter named i. This parameter is not the same variable as the local variable i in the main function, but the value of i in the main function was passed as an argument to prIt.
By the way, you should declare functions with a return type, and here both functions should have an int return type. Also, since you use printf(), you should #include <stdio.h>.
Look up a C++ Reference and learn How To Ask Questions The Smart WayOriginally Posted by Bjarne Stroustrup (2000-10-14)
You are helpful, thank you!
This may be off the topic, but what is the difference between static local variables and global variables?
One obvious difference is the scope of the variables.
Look up a C++ Reference and learn How To Ask Questions The Smart Way
I see. "Static simply means that the local variable's value is still there if the program calls the function again."
Thank you!
