fscanf() floating point error

Does scanf() have a known problem with floating points when used as below?

Code:

while( (scoresScanned = scanf("%f%f%f", &score1, &score2, &score3)) != EOF  ){

			if( scoresScanned == 3 ){
				fflush(stdin);
				break;
			}
			else/.../
		}

If it do 4.4 5.5 abc it fails like I want it to.
BUT
If I do 4.4 5.5 4abc5 it thinks I entered 4.0 as the last value.

My understanding of scanf() is that it should fail and return 2 in the latter case.

Why does scanf() do that? I hoped it would fail instead of truncate the input and append a .0. Perhaps there is a great document of this but I haven't found one.

I'm studying C in school which would explain why I'm asking about a deprecated function in the first place.


Thanks,

James
----
MS VC++ 2005 Express
C++ Language Extentions Off \Za
Compiling as C code \Tc

No, scanf makes a best attempt of reading as much as possible of whatever is fed into it until it finds something that is wrong. So if you have a %f format, and give it 4abc, it will read 4 and say "Yes, I got something". It doesn't know that you are NOT expecting to see a %s in the next scanf statement.

Also:

Code:

				fflush(stdin);

is undefined. fflush, in the standard, is only defined for OUTPUT streams, not input streams. It MAY do what you want, but it's also perfectly within the C library producers right to format your hard-disk, spew out garbage, thrash some random bit of memory, do nothing, crash the application or something else. That's the unfortunate thing about "undefined behaviour" - it is not defined, and may do many different things, depending on circumstances.

--
Mats