Help for my output array

qwertysingh · 02-17-2009, 02:57 PM

Hi Guys, I having trouble with my output array. The system works fine, in that it takes input from the user and runs the correct logic and then ouputs it.

I have decided to include an output array, so; 1) The user selects the logic gate they want to test.
2) The user then selects how many inputs they would like.
*3) I have just decided to add this in, the user then selects how many outputs they would like.
4) The user then sets the values for the inputs.

What I am having a problem with now is that I would like the system to printf() the output as many times specified by the user.

eg, An AND gate has been selected, and 2 inputs have been declared and 3 outputs have been declared, the input values have been assigned to the input array. Once the gate has applied the bitwise operator, it outputs the response to the command prompt. I want it to display as so; Output = [1,1,1]. Instead of just Output = 1 or 0, I want it to output as many times as the user specified for the output array.

Here is what I have;

Code:

...int and(int n, int o)
{
	printf("\nPlease Set The Values For Your Inputs: ");
	int array[n]; ..input array
	int output[o]; //the output array

	int i = 0;
	for (i = 0; i < n; i++){
		printf("Enter input %d:", i);
		scanf("%d",&array[i]);
		while(array[i]!=0 && array[i]!=1){
			printf("Value must be 0 or 1. Please try again:\n");
			scanf("%d",&array[i]);
		}
	}

	int result = array[0];
	for(i = 1; i < n; i++)
	{
	   result &= array[i];
	}

	printf("\nOuptut = %d\n", result);

	/*int j = 0;
	for (j=0; j < o; j++){
		printf("%d", output[j]); //Just to see if it worked, but nope
	}*/

Thanks

MK27 · 02-17-2009, 03:08 PM

How 'bout another "for" loop nesting from here:

Quote:

Code:

		}
	}

	int result = array[0];
	for(i = 1; i < n; i++)

Of course maybe then you want to move the declaration up.

02-17-2009, 02:57 PM	#1
qwertysingh Registered User Join Date: Feb 2009 Posts: 19	Help for my output array Hi Guys, I having trouble with my output array. The system works fine, in that it takes input from the user and runs the correct logic and then ouputs it. I have decided to include an output array, so; 1) The user selects the logic gate they want to test. 2) The user then selects how many inputs they would like. 3) I have just decided to add this in, the user then selects how many outputs they would like. 4) The user then sets the values for the inputs. What I am having a problem with now is that I would like the system to printf() the output as many times specified by the user. eg, An AND gate has been selected, and 2 inputs have been declared and 3 outputs have been declared, the input values have been assigned to the input array. Once the gate has applied the bitwise operator, it outputs the response to the command prompt. I want it to display as so; Output = [1,1,1]. Instead of just Output = 1 or 0, I want it to output as many times as the user specified for the output array. Here is what I have; Code: ...int and(int n, int o) { printf("\nPlease Set The Values For Your Inputs: "); int array[n]; ..input array int output[o]; //the output array int i = 0; for (i = 0; i < n; i++){ printf("Enter input %d:", i); scanf("%d",&array[i]); while(array[i]!=0 && array[i]!=1){ printf("Value must be 0 or 1. Please try again:\n"); scanf("%d",&array[i]); } } int result = array[0]; for(i = 1; i < n; i++) { result &= array[i]; } printf("\nOuptut = %d\n", result); /int j = 0; for (j=0; j < o; j++){ printf("%d", output[j]); //Just to see if it worked, but nope }*/ Thanks
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