doubt in printf ??

I m getting only "This is". as output.

How ????

Code:

printf("This is \x0x65 C \x0x66");

What did you expect to get? Note that '\x0' is 0, so you are effectively terminating the string at that point.

Originally Posted by ganesh bala

I m getting only "This is". as output.

How ????

Code:

printf("This is \x0x65 C \x0x66");

is this what you want to see? if not.. tell us

Code:

printf("This is %c %c %c", '\x0x65', 'C', '\x0x66' );

If you want to show hex character 0x65, then you should use \x065. As it stands, character constants are malformed. The compiler doesn't detect it, as it is technically a valid string. In $l4xklynx post, it turns to a multi-character constant, and it is probably undefined behaviour exactly what it prints in this case.

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Mats